如何在python中以键值对的形式打印数组?

使用列出理解 enumerate 是一种方式。请注意每个单项键后的逗号。这表示对象类型是 元组 长度为1。

from numpy import array

a = [array([0, 1, 2, 3, 4]), array([0, 1, 2, 3]), array([0, 1, 2, 3, 4]),
     array([0, 1, 2, 3, 4, 5, 6, 7, 8]), array([0, 2, 3, 4, 5, 8, 9])]

res = [[(i,), tuple(j for j in arr if j != i)] for i, arr in enumerate(a)]

# [[(0,), (1, 2, 3, 4)],
#  [(1,), (0, 2, 3)],
#  [(2,), (0, 1, 3, 4)],
#  [(3,), (0, 1, 2, 4, 5, 6, 7, 8)],
#  [(4,), (0, 2, 3, 4, 8, 9)]]

或者,您可以创建字典:

res_dict = {i: tuple(j for j in arr if j != i) for i, arr in enumerate(a)}

# {0: (1, 2, 3, 4),
#  1: (0, 2, 3),
#  2: (0, 1, 3, 4),
#  3: (0, 1, 2, 4, 5, 6, 7, 8),
#  4: (0, 2, 3, 4, 8, 9)}

您可以尝试numpy方法:

import numpy as np

a = [np.array([0, 1, 2, 3, 4]),np.array([0, 1, 2, 3]),np.array([0, 1, 2, 3, 4]),
     np.array([0, 1, 2, 3, 4, 5, 6, 7, 8]), np.array([0, 2, 3, 4, 5, 8, 9])]

print([[(i,),tuple(np.delete(j,np.argwhere(j==i)))] for i,j in enumerate(a)])

输出:

[[(0,), (1, 2, 3, 4)], [(1,), (0, 2, 3)], [(2,), (0, 1, 3, 4)], [(3,), (0, 1, 2, 4, 5, 6, 7, 8)], [(4,), (0, 2, 3, 5, 8, 9)]]