Javascript Object,返回一个新数组,其中包含与该对象匹配的索引[重复]

// Set up - code copied from OP
league  = {};
league.venue  = [];
league.venue[0] = {};
league.venue[0].code  = 1000;
league.venue[0].team  = "Arsenal";

league.venue[1] = {};
league.venue[1].code  = 1001;
league.venue[1].team  = "Spurs";

league.venue[2] = {};
league.venue[2].code  = 1002;
league.venue[2].team  = "Liverpool";

league.venue[3] = {};
league.venue[3].code  = 1003;
league.venue[3].team  = "Manchester City";

league.venue[4] = {};
league.venue[4].code  = 1004;
league.venue[4].team  = "Manchester United";

league.venue[5] = {};
league.venue[5].code  = 1005;
league.venue[5].team  = "Everton";

league.code = [1004, 1005, 1000, 1003, 1002]

// Solution - find each code in league.venue array:
const result = league.code.map(c => league.venue.findIndex(v => c === v.code));
console.log(result);

const
    league = { venue: [{ code: 1000, team: "Arsenal" }, { code: 1001, team: "Spurs" }, { code: 1002, team: "Liverpool" }, { code: 1003, team: "Manchester City" }, { code: 1004, team: "Manchester United"}, { code: 1005, team: "Everton" }], code: [1004, 1005, 1000, 1003, 1002] },
    targets = Object.fromEntries(Object
        .entries(league.code)
        .map(([k, v]) => [v, k])
    ),
    result = league.venue.reduce(
        (r, { code }, i) => r.with(targets[code], i),
        Array(league.code.length)
    );

console.log(result);