基于内容筛选字符串列表时出错-python

假设您的国家有多个单词的国家名称,用空格隔开(在您的问题中),而不是 _ .

你可以这样做:

countries = ['UNITED STATES',
            'CHINA',
            'GERMANY'
            ]
commit = [['UNITED_STATES-Consumer1_SymPercChg'],
      ['UNITED_STATES-Housing1_StndDev'],
      ['UNITED_STATES-Auto1_SymPercChg'],
      ['CHINA-Finance1_SymPercChg'],
      ['CHINA-Transport1_StndDev'],
      ['CHINA-Housing1_SymPercChg'],
      ['GERMANY-PMI1_StndDev'],
      ['GERMANY-Manufacturing1_SymPercChg'],
      ['GERMANY-Survey1_SymPercChg']
     ]
for c in countries:
    c = "_".join(c.split(" "))
    print c, [x for x in commit if c in x[0]]

输出:

UNITED_STATES ['UNITED_STATES-Consumer1_SymPercChg', 'UNITED_STATES-Housing1_StndDev', 'UNITED_STATES-Auto1_SymPercChg']


CHINA ['CHINA-Finance1_SymPercChg', 'CHINA-Transport1_StndDev', 'CHINA-Housing1_SymPercChg']

GERMANY ['GERMANY-PMI1_StndDev', 'GERMANY-Manufacturing1_SymPercChg', 'GERMANY-Survey1_SymPercChg']

试一试 regex match .

import re

pattern = re.compile('(^[A-Z_]+)(-)(.+)')
country_data = {}

for c in commit:
    match = pattern.match(c[0])
    if match:
        if match.group(1) in countries:
            if match.group(1) in country_data.keys():
                country_data[match.group(1)].append(match.string)
            else:
                country_data[match.group(1)] = [match.string]

print(country_data)