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打开内部numpy阵列的包装

numpy arrays python

Rogério Gouvêa · 技术社区 · 2 年前

我有以下numpy阵列:

a=[['Sb' array([4.24035696, 2.44817292, 7.41858935])]
 ['I' array([2.08076032, 3.69501392, 5.37518666])]
 ['I' array([6.35173963, 1.22916823, 8.9947238 ])]
 ['I' array([ 4.24036048, -0.04551256,  5.37518684])]
 ['I' array([4.24035383, 4.88618543, 8.99472472])]
 ['I' array([6.3999514 , 3.69501663, 5.37518685])]
 ['I' array([2.12897688, 1.22916548, 8.99472467])]]

我想打开内部阵列的包装,以便:

a=[['Sb' 4.24035696 2.44817292 7.41858935]
 ...
 ['I' 2.12897688 1.22916548 8.99472467]]

我无法用一种简单的方式来理解这个问题。

1 回复 | 直到 2 年前

hpaulj 2 年前

请参见我的评论以获取解释:

In [142]: array=np.array
     ...: a=np.array([['Sb', array([4.24035696, 2.44817292, 7.41858935])],
     ...:  ['I', array([2.08076032, 3.69501392, 5.37518666])],
     ...:  ['I', array([6.35173963, 1.22916823, 8.9947238 ])],
     ...:  ['I', array([ 4.24036048, -0.04551256,  5.37518684])],
     ...:  ['I', array([4.24035383, 4.88618543, 8.99472472])],
     ...:  ['I', array([6.3999514 , 3.69501663, 5.37518685])],
     ...:  ['I', array([2.12897688, 1.22916548, 8.99472467])]], dtype=object)

In [143]: a
Out[143]: 
array([['Sb', array([4.24035696, 2.44817292, 7.41858935])],
       ['I', array([2.08076032, 3.69501392, 5.37518666])],
       ['I', array([6.35173963, 1.22916823, 8.9947238 ])],
       ['I', array([ 4.24036048, -0.04551256,  5.37518684])],
       ['I', array([4.24035383, 4.88618543, 8.99472472])],
       ['I', array([6.3999514 , 3.69501663, 5.37518685])],
       ['I', array([2.12897688, 1.22916548, 8.99472467])]], dtype=object)

In [144]: a[:,0]
Out[144]: array(['Sb', 'I', 'I', 'I', 'I', 'I', 'I'], dtype=object)

In [145]: np.stack(a[:,1])
Out[145]: 
array([[ 4.24035696,  2.44817292,  7.41858935],
       [ 2.08076032,  3.69501392,  5.37518666],
       [ 6.35173963,  1.22916823,  8.9947238 ],
       [ 4.24036048, -0.04551256,  5.37518684],
       [ 4.24035383,  4.88618543,  8.99472472],
       [ 6.3999514 ,  3.69501663,  5.37518685],
       [ 2.12897688,  1.22916548,  8.99472467]])

将它们组合到对象数据类型数组中:

In [148]: res = np.concatenate((a[:,[0]],np.stack(a[:,1])),axis=1,dtype=object)

In [149]: res
Out[149]: 
array([['Sb', 4.24035696, 2.44817292, 7.41858935],
       ['I', 2.08076032, 3.69501392, 5.37518666],
       ['I', 6.35173963, 1.22916823, 8.9947238],
       ['I', 4.24036048, -0.04551256, 5.37518684],
       ['I', 4.24035383, 4.88618543, 8.99472472],
       ['I', 6.3999514, 3.69501663, 5.37518685],
       ['I', 2.12897688, 1.22916548, 8.99472467]], dtype=object)