如何用python裁剪和插值图像的一部分[复制]

我已经用过 interp2 在Matlab中,例如下面的代码,这是@rayryeng在中的答案的一部分: Three dimensional (3D) matrix interpolation in Matlab :

d = size(volume_image)
[X,Y] = meshgrid(1:1/scaleCoeff(2):d(2), 1:1/scaleCoeff(1):d(1));
for ind = z
    %Interpolate each slice via interp2   
    M2D(:,:,ind) = interp2(volume_image(:,:,ind), X, Y);   
end

尺寸示例:

The image size is 512x512 and the number of slices is 133. So:
volume_image(rows, columns, slices in 3D dimenson) : 512x512x133 in 3D dimenson
X: 288x288
Y: 288x288
scaleCoeff(2): 0.5625
scaleCoeff(1): 0.5625
z = 1 up to 133 ,hence z: 1x133
ind: 1 up to 133
M2D(:,:,ind) finally is 288x288x133 in 3D dimenson

aslo,matlabs syntax for size:(rows,columns,slices in 3rd dimenson)和python syntax for size:(slices in 3rd dim,rows,columns)。 但是,在将Matlab代码转换为Python代码之后发生了一个错误, ValueError: Invalid length for input z for non rectangular grid :

for ind in range(0, len(z)+1):
    M2D[ind, :, :] = interpolate.interp2d(X, Y, volume_image[ind, :, :]) # ValueError: Invalid length for input z for non rectangular grid

怎么了?非常感谢。