创建不使用虚拟基类的对象的克隆

#include<iostream>
using namespace std;

class Something
{
  public:
  int j;
  Something():j(20) {cout<<"Something initialized. j="<<j<<endl;}
};

class Base
{
  private:
    Base(const Base&) {}
  public:
    Base() {}
    virtual Base *clone() { return new Base(*this); }
    virtual void ID() { cout<<"BASE"<<endl; }
};

class Derived : public Base
{
  private:
    int id;
    Something *s;
    Derived(const Derived&) {}
  public:
    Derived():id(10) {cout<<"Called constructor and allocated id"<<endl;s=new Something();}
    ~Derived() {delete s;}
    virtual Base *clone() { return new Derived(*this); }
    virtual void ID() { cout<<"DERIVED id="<<id<<endl; }
    void assignID(int i) {id=i;}
};


int main()
{
        Base* b=new Derived();
        b->ID();
        Base* c=b->clone();
        c->ID();
}//main

运行时:

Called constructor and allocated id
Something initialized. j=20
DERIVED id=10
DERIVED id=0

我的问题与 this , this 和 this

在第一个链接中,Space_C0wb0y说

“因为克隆方法是 同时创建深拷贝。它可以访问 它所属班级的所有成员 所以没有问题。”

我不明白怎么会发生深度复制。在上面的程序中,甚至没有一个浅拷贝发生。 即使基类是抽象类,我也需要它工作