php-检查是否有任何嵌套数组不为空

你需要分三步做

• 检查每个元素是否为数组()
• 如果是,请检查大小($element)
• 如果大于0,则为真,否则为假

更优雅?不,我不这么认为。实际上,你可以在第一次非空后断开回路,使这个检查短路,这是一个微小的改进,但这是实现的方法。

使用array_walk(我相信几分钟后会提到)速度较慢,可读性较差;此外,序列化(通过strpos或regex查找非空日期字符串)也有一些棘手的解决方案,但应用它们不会获得任何好处。

坚持这个解决方案,并在第一次击中时使用休息。#切夫斯蒂普;)

使用第二个参数 count 将计算数组中的所有项,包括子数组。这并不是像其他答案那样适用于所有情况的解决方案,并且有一些不清楚的初步假设,但仍然:

// Suppose you have array of your structure
$myArray =  [ 
    '1' =>  ['dates' => []],
    '2' =>  ['dates' => []],
    '3' =>  ['dates' => []],
];
// compare 
var_dump(count($myArray), count($myArray, true));
// you see `3` and `6` 
//  - 3 is count of outer elements
//  - 6 is count of all elements

// Now if there're no other keys in subarrays except `dates` 
// you can expect that `count` of all elements is __always__
// twice bigger than `count` of outer elements

// When you add some value to `dates`:
$myArray =  [ 
    '1' =>  ['dates' => ['date-1']],
    '2' =>  ['dates' => []],
    '3' =>  ['dates' => []],
];
// compare 
var_dump(count($myArray), count($myArray, true));
// you see `3` (outer elements) and `7` (all elements)
// So, you have __not empty__ `dates` when `count` of all elements 
// is more than doubled count of outer elements:

$not_empty_dates = 2 * count($myArray) < count($myArray, true);

// Of course if you have other keys in subarrays
// code should be changed accordingly, that's why
// it is not clear solution, but still it can be used

工作小提琴 https://3v4l.org/TanG4 .