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如何用两个大小相等的数组构建Ruby散列?

hash arrays ruby

83

maÄek · 技术社区 · 15 年前

a = [:foo, :bar, :baz, :bof]

和

b = ["hello", "world", 1, 2]

{:foo => "hello", :bar => "world", :baz => 1, :bof => 2}

有什么办法吗?

3 回复 | 直到 15 年前

1

208

jtbandes 15 年前

h = Hash[a.zip b] # => {:baz=>1, :bof=>2, :bar=>"world", :foo=>"hello"}

…该死,我爱鲁比。

2

38

Lethjakman 12 年前

我只想指出有一个稍微干净一点的方法:

h = a.zip(b).to_h # => {:foo=>"hello", :bar=>"world", :baz=>1, :bof=>2}

3

16

Junichi Ito 12 年前

这个怎么样?

[a, b].transpose.to_h

如果使用Ruby 1.9:

Hash[ [a, b].transpose ]

a.zip(b) 看起来像 a 是主人和 b

4

1

the Tin Man 6 年前

只是出于好奇:

require 'fruity'

a = [:foo, :bar, :baz, :bof]
b = ["hello", "world", 1, 2]

compare do
  jtbandes { h = Hash[a.zip b] }
  lethjakman { h = a.zip(b).to_h }
  junichi_ito1 { [a, b].transpose.to_h }
  junichi_ito2 { Hash[ [a, b].transpose ] } 
end

# >> Running each test 8192 times. Test will take about 1 second.
# >> lethjakman is similar to junichi_ito1
# >> junichi_ito1 is similar to jtbandes
# >> jtbandes is similar to junichi_ito2

compare do 
  junichi_ito1 { [a, b].transpose.to_h }
  junichi_ito2 { Hash[ [a, b].transpose ] } 
end

# >> Running each test 8192 times. Test will take about 1 second.
# >> junichi_ito1 is faster than junichi_ito2 by 19.999999999999996% Â± 10.0%