如何用两个大小相等的数组构建Ruby散列?

h = Hash[a.zip b] # => {:baz=>1, :bof=>2, :bar=>"world", :foo=>"hello"}

…该死,我爱鲁比。

我只想指出有一个稍微干净一点的方法:

h = a.zip(b).to_h # => {:foo=>"hello", :bar=>"world", :baz=>1, :bof=>2}

这个怎么样?

[a, b].transpose.to_h

如果使用Ruby 1.9:

Hash[ [a, b].transpose ]

a.zip(b) 看起来像 a 是主人和 b

只是出于好奇:

require 'fruity'

a = [:foo, :bar, :baz, :bof]
b = ["hello", "world", 1, 2]

compare do
  jtbandes { h = Hash[a.zip b] }
  lethjakman { h = a.zip(b).to_h }
  junichi_ito1 { [a, b].transpose.to_h }
  junichi_ito2 { Hash[ [a, b].transpose ] } 
end

# >> Running each test 8192 times. Test will take about 1 second.
# >> lethjakman is similar to junichi_ito1
# >> junichi_ito1 is similar to jtbandes
# >> jtbandes is similar to junichi_ito2

compare do 
  junichi_ito1 { [a, b].transpose.to_h }
  junichi_ito2 { Hash[ [a, b].transpose ] } 
end

# >> Running each test 8192 times. Test will take about 1 second.
# >> junichi_ito1 is faster than junichi_ito2 by 19.999999999999996% ± 10.0%