mysqli语句:fetch()结果数组

您可以实现自己的uuClone()魔术函数,这样它将创建一个未引用的对象副本。我认为它应该起作用。

http://www.php.net/manual/en/language.oop5.cloning.php

<?php

class Item {
  public $id, $name;

  public function __clone() {
    $id = $this->id;
    unset($this->id);
    $this->id = $id;
    $name = $this->name;
    unset($this->name);
    $this->name = $name;
  }
}

$id = 1;
$name = 'o_0 Tync';

$i1 = new Item();
$i1->id = &$id;
$i1->name = &$name;

$i2 = clone $i1;

$id = 2;
$name = 'Mchl';
var_dump($i1,$i2);

产量

object(Item)#1 (2) {
  ["id"]=>
  &int(2)
  ["name"]=>
  &string(4) "Mchl"
}
object(Item)#2 (2) {
  ["id"]=>
  int(1)
  ["name"]=>
  string(8) "o_0 Tync"
}

丑陋得要命,但有用…

如果我正确理解您,您想将数据提取到对象中吗?mysqli有一个fetch对象方法/函数: http://www.php.net/manual/en/mysqli-result.fetch-object.php 这样使用:

$foobar = $conn->escape_string($foobar);
$stmt = $conn->query("SELECT * FROM foo WHERE bar = '$foobar'");
while ($item = $stmt->fetch_object("Item")) {
    $items[] = $item;
}
$stmt->close();