您可能能够完全避免处理numpy c api。python可以使用
ctypes
模块,您可以使用数组的ctypes属性访问指向numpy数据的指针。
这里有一个最小的例子,展示了一维平方和函数的过程。
C方
#include <stdlib.h>
float mysumsquares(float * array, size_t size) {
float total = 0.0f;
size_t idx;
for (idx = 0; idx < size; ++idx) {
total += array[idx]*array[idx];
}
return total;
}
编译到ctsquare.so
这些命令行是针对OSX的,您的操作系统可能会有所不同。
$ gcc -O3 -fPIC -c ctsquare.c -o ctsquare.o
$ ld -dylib -o ctsquare.so -lc ctsquare.o
Py
import numpy
import ctypes
# pointer to float type, for convenience
c_float_p = ctypes.POINTER(ctypes.c_float)
# load the library
ctsquarelib = ctypes.cdll.LoadLibrary("ctsquare.so")
# define the return type and arguments of the function
ctsquarelib.mysumsquares.restype = ctypes.c_float
ctsquarelib.mysumsquares.argtypes = [c_float_p, ctypes.c_size_t]
# python front-end function, takes care of the ctypes interface
def myssq(arr):
# make sure that the array is contiguous and the right data type
arr = numpy.ascontiguousarray(arr, dtype='float32')
# grab a pointer to the array's data
dataptr = arr.ctypes.data_as(c_float_p)
# this assumes that the array is 1-dimensional. 2d is more complex.
datasize = arr.ctypes.shape[0]
# call the C function
ret = ctsquarelib.mysumsquares(dataptr, datasize)
return ret
if __name__ == '__main__':
a = numpy.array([1,2,3,4])
print 'sum of squares of [1,2,3,4] =', myssq(a)