在Pandas中基于带分隔符的依存列解析值

def f(x):
    p = dict(zip(x['col1'].split(":"),x['col2'].split(":")))
    return p['c']

df.apply(f,axis=1).astype(int).rename('c')

或者,如果你想要lambda:

df.apply(lambda x: dict(zip(x['col1'].split(":"),x['col2'].split(":")))['c'],axis=1).astype(int).rename('c')

输出:

0    2
1    7
Name: c, dtype: int32