把一本大字典分成一个小字典

# create some dictionary
x = {i: 'z' + str(i) for i in range(1, 22+1)}

def get_chunks(x, size=10):
    out = {}
    for i, k in enumerate(x, 1):
        if i % size == 0:
            yield out
            out = {}
        out[k] = x[k]
    # last chunk:
    if out:
        yield out

for chunk in get_chunks(x):
    print(chunk)

{1: 'z1', 2: 'z2', 3: 'z3', 4: 'z4', 5: 'z5', 6: 'z6', 7: 'z7', 8: 'z8', 9: 'z9'}
{10: 'z10', 11: 'z11', 12: 'z12', 13: 'z13', 14: 'z14', 15: 'z15', 16: 'z16', 17: 'z17', 18: 'z18', 19: 'z19'}
{20: 'z20', 21: 'z21', 22: 'z22'}

print(list(get_chunks(x)))

itertools 10

list(map(dict, zip(*[iter(x.items())] * 10)))

对于你的问题,一个直截了当、极其难看的答案是这样的:

import itertools

def slice_it_up(d, n):
    return [{x for x in itertools.islice(d.items(), i, i+n)} for i in range(0, len(d), n)]

d = {'key1': 1, 'key2': 2, 'key3': 3, 'key4': 4, 'key5': 5}
dd = slice_it_up(d, 3)

print(dd)

[{('key2', 2), ('key1', 1), ('key3', 3)}, {('key5', 5), ('key4', 4)}]