杰克逊反序列化Scala的未来

我试图解释Jersey和Jackson如何反序列化我作为字节[]传递的未来。

我创建自己的ContextResolver

public class ObjectMapperContextResolver implements ContextResolver<ObjectMapper> {

    private static ObjectMapper mapper = null;

    public ObjectMapperContextResolver() {
        mapper = ObjectMapperFactory.getObjectMapper();     
    }

    @Override
    public ObjectMapper getContext(Class<?> type) {
        return mapper;
    }

}

以及ObjectMapper的实现

public static ObjectMapper getObjectMapper() {
        ObjectMapper defaultObjectMapper = new ObjectMapper();
        SimpleModule futureModule = new SimpleModule("FutureModule");
        futureModule.<Future>addDeserializer(Future.class, new FutureDeserializer<String>());
        defaultObjectMapper.registerModule(futureModule);
        return defaultObjectMapper;
}

最后在我的FutureDeserializer的实现中

public class FutureDeserializer<T> extends StdDeserializer<Future<T>>{

    public FutureDeserializer() {
        super(Future.class);
    }

    @Override
    public Future<T> deserialize(JsonParser jp, DeserializationContext ctxt)
            throws IOException {
        ObjectMapper mapper=(ObjectMapper)jp.getCodec();
        //TODO: Breakpoint never stop here
        return null;
    }
}

然后我在我的 ResourceConfig 在比赛开始前 JerseyTest

ResourceConfig rc = new ResourceConfig();
        rc.register(SpringLifecycleListener.class);
        rc.register(RequestContextFilter.class);
        rc.register(new JacksonFeature());
        rc.register(new ObjectMapperContextResolver());

但是当我运行测试时,ObjectMapperContextResolver被调用,映射程序返回到Jersey,但他从未使用FutureDeserializer。

知道我做错了什么吗?