模板化函数指针

我有一种方法调用类的延迟函数:

//in MyClass declaration:
typedef void (MyClass::*IntFunc) (int value);
void DelayedFunction (IntFunc func, int value, float time);
class TFunctorInt
{
public:
    TFunctorInt (MyClass* o, IntFunc f, int v) : obj (o), func (f), value (v) {}
    virtual void operator()();
protected:
    MyClass* obj;
    IntFunc func;
    int value;
};
//in MyClass.cpp file:
void MyClass::DelayedFunction (IntFunc func, int value, float time)
{
    TFunctorBase* functor = new TFunctorInt (this, func, value);
    DelayedFunctions.push_back (TDelayedFunction (functor, time)); // will be called in future
}
void MyClass::TFunctorInt::operator()()
{
    ((*obj).*(func)) (value);
}

我想做模板函数。第一个问题是:

template <typename T>
typedef void (MyClass::*TFunc<T>) (T param);

导致编译器错误:“typedef”的模板声明。 什么可能是解决方案?

PS:代码基于 http://www.coffeedev.net/c++-faq-lite/en/pointers-to-members.html#faq-33.5