无法理解python 2d矩阵的输出

我尝试以螺旋格式打印值1到9,如下所示:

[1,2,3]
[8,9,4]
[7,6,5]

但是,当我试图通过一个Python脚本(写在下面)打印它时,它会覆盖它。我得到了正确的索引和值。我只是不能给正确的索引赋值。脚本是:

n = 3
res = [[0]*n]*n

    count = 1

    def getcoord(r1,c1,r2,c2):
        for c in range(c1, c2+1):
            yield r1, c
        for r in range(r1+1, r2+1):
            yield r,c2
        if r1 < r2 and c1 < c2:
            for c in range(c2-1, c1-1, -1):
                yield r2,c
            for r in range(r2-1, r1, -1):
                yield r, c1


    r1 = 0
    r2 = n-1
    c1= 0
    c2 = n-1
    val = 1
    while r1<=r2 and c1<=c2:
        for r,c in getcoord(r1,c1,r2,c2):
            print(r,c)
            print("val", val)
            res[r][c] = val
            print("res", res)
            val += 1
        r1 += 1; r2 -= 1
        c1 += 1; c2 -= 1
    return res

当我尝试调试时,我得到如下输出:

(0, 0)
('val', 1)
('res', [[1, 0, 0], [1, 0, 0], [1, 0, 0]])
(0, 1)
('val', 2)
('res', [[1, 2, 0], [1, 2, 0], [1, 2, 0]])
(0, 2)
('val', 3)
('res', [[1, 2, 3], [1, 2, 3], [1, 2, 3]])
(1, 2)
('val', 4)
('res', [[1, 2, 4], [1, 2, 4], [1, 2, 4]])
(2, 2)
('val', 5)
('res', [[1, 2, 5], [1, 2, 5], [1, 2, 5]])
(2, 1)
('val', 6)
('res', [[1, 6, 5], [1, 6, 5], [1, 6, 5]])
(2, 0)
('val', 7)
('res', [[7, 6, 5], [7, 6, 5], [7, 6, 5]])
(1, 0)
('val', 8)
('res', [[8, 6, 5], [8, 6, 5], [8, 6, 5]])
(1, 1)
('val', 9)
('res', [[8, 9, 5], [8, 9, 5], [8, 9, 5]])

我这里缺什么?为什么我不能将正确的值赋给正确的索引,尽管两者都有? 事先谢谢!