C++错误LNK2019和致命错误LNK1120:1未解决的外部问题

我正在努力为学校做家庭作业,我的任务比老师要求的要高--我已经创建了一个“列表”类。在将“add()”方法和“newIncoMetax()”方法添加到程序之后,我一直遇到这两个错误。

错误LNK2019:未解析的外部符号“public:void uuu thiscall list::add(class incometax*)”(?添加在函数\u main driver.obj中引用的@list@@qaexpavincometax@@z)

和

致命错误LNK1120:1个无法解析的外部变量

我希望这足够任何人帮助我的代码:

注意:下面的函数与它们在原始代码中出现的顺序不同 (如果这可能是问题所在,我可以提供我正在使用的所有代码)

H表

#ifndef LIST_H
#define LIST_H

#include "IncomeTax.h"
class List
{
private:
    IncomeTax * First;
    IncomeTax * Last;
    int num_in_list;
public:
    List () { num_in_list = 0; First = NULL; Last = NULL; }
    int get_num_in_list() { return num_in_list; }
    IncomeTax * getFirst() { return First; }
    IncomeTax * getLast() { return Last; }
    void del_frnt ();
    void push_front (IncomeTax *);
    void push_back (IncomeTax *);
    void del_last ();
    void add (IncomeTax*);
    IncomeTax * pop_back ();
    IncomeTax * pop_front ();
    IncomeTax * get (int);
};
#endif

注意:从我所看到的列表中,**我所做的**与默认的行为类似。

list.cpp中的“add”方法

void List:: add (IncomeTax * IncomeTax_to_be_added) {
    if (num_in_list == 0) { First = IncomeTax_to_be_added; Last = IncomeTax_to_be_added; }
    else if (num_in_list != 0 ) {
        Last->setNext(IncomeTax_to_be_added);
        IncomeTax_to_be_added->setPrevous(Last);
        Last = IncomeTax_to_be_added;
    }
    num_in_list++;
}

国际贸易协会

#ifndef INCOME_TAX
#define INCOME_TAX

#include <iostream>
#include <string>
#include "conio.h"
#include <cassert>
using namespace std;

class IncomeTax {
private:
    double incm;
    double ajIncm;
    double subtract;
    double taxRate;
    double add;
    bool married;

    void calcIncome_m ();
    void calcIncome_s ();
public:
    IncomeTax () { incm = 0; subtract = 0; taxRate = 0; add = 0; add = false; }
    // married -> is by default false
    void setmarried ( bool stats ) { married = stats; }
    void setIncm (double in ) { incm = in; }
    void setSubtract ( double sub ) { subtract = sub; }
    void setTaxRate ( double rate ) { taxRate = rate; }
    void setAdd ( double Add ) { add = Add; }
    void setAjIncome ( double AJincome ) { ajIncm = AJincome; }

    bool getmarried () { return married; }
    double getIncm () { return incm; }
    double getsubtract () { return subtract; }
    double getTaxRate () { return taxRate; }
    double getAdd () { return add; }
    double getAJincome () { return ajIncm; }
    void calcIncome ();
    void pintIncome ();
};

#endif

英科托克斯普

#include "IncomeTax.h"
using namespace std;

void IncomeTax::calcIncome(){
    assert (incm != 0);
    if (married) { calcIncome_m(); }
    if (!married) { calcIncome_s(); }

    ajIncm = (incm - subtract);
    ajIncm -= (ajIncm * taxRate);
    ajIncm += add; 
}

void IncomeTax::calcIncome_m() {
    assert (incm != 0);
    ... huge nested if statements ... 
    they set subtract, add, taxRate...
}

void IncomeTax::calcIncome_s() {
    assert (incm != 0);
    ... huge nested if statements ... 
    they set subtract, add, taxRate...
}

void IncomeTax::pintIncome () {
    assert (incm != 0);
    assert (ajIncm != 0);

    std::cout.precision(2);
    cout << "\tTaxable Income: " << incm << endl;
    cout << "\tAjusted Income: " << ajIncm << endl;
    cout << "\tTax: " << (incm - ajIncm) << "\n" << endl;
}

驱动程序CPP

#include <conio.h>
#include <iostream>
#include <string>
#include <cassert>
#include "IncomeTax.h"
#include "List.h"
using namespace std;

void getMaritalStatus( IncomeTax new_tax) {
    bool done = false;
    char stt = ' ';
    while ( !done ) {
        cout << "\nPlease declare weather you are filing taxes jointly or single" << "\n";
        cout << "\t's' = single\n\t'm' = married" << endl;
        stt = getch();
        if ( stt == 's' || stt == 'm' ) { done = true; }
        if ( stt == 's' ) { new_tax.setmarried(true); }
        if ( ! (stt == 's' || stt == 'm') ) { cout << "\nyou have entered an invald symbol... \n" << endl; }
        if(cin.fail()) { cin.clear(); }
        }
    }


void get_Income ( IncomeTax new_tax) {
    double _incm = 0;
    char status = ' ';
    bool done = true;
    while ( done ) {
        cout << "Please enter your TAXABLE INCOME:" << endl;
        cin >> _incm;
        if ( _incm > 0 ) { new_tax.setIncm(_incm); done = false; }
        if ( _incm <= 0 ) { cout << "\nthe number you entered was less than zero\nplease enter a valad number...\n" << endl; } 
        if(cin.fail()) { cin.clear(); }
    }
    }

IncomeTax newIncomeTax () {
    IncomeTax new_tax;
    IncomeTax * temp;
    get_Income(new_tax);
    getMaritalStatus(new_tax);
    new_tax.calcIncome();
    return new_tax;
}

bool again () {
    bool done = false, answer = false;
    char yn = ' ';
    while ( !done ) {
        cout << "\nWould you like to calculate another Income tax? (y/n)" << endl;
        yn = getch();
        if ( yn == 'y' || yn == 'n' ) { done = true; }
        if ( yn == 'y' ) { return false; }
        if ( yn == 'n' ) { return true; }
        if ( ! (yn == 's' || yn == 'n') ) { cout << "\nyou have entered an invald symbol... \n" << endl; }
        if(cin.fail()) { cin.clear(); }
        }
    }

int main () {
    IncomeTax new_tax;
    List L;
    bool done = false;
    while (!done) {
        IncomeTax temp = newIncomeTax();
        IncomeTax * ptr = &temp;
        L.add(ptr);
        done = again();
        };

    return 0;
};

我知道有很多更好的方法来做“如果”的陈述--我只是决定使用“如果”的陈述是有效的--教授说没有必要超过这一点。

因为这是家庭作业,我很想得到一些反馈,关于如何使用更好的编程技术。谢谢!

我使用VS Express 2008 C++