如何制作JAXB对象的深度副本,如xmlbean XmlObject.copy()?

你可以参考这个

public static <T> T deepCopyJAXB(T object, Class<T> clazz) {
  try {
    JAXBContext jaxbContext = JAXBContext.newInstance(clazz);
    JAXBElement<T> contentObject = new JAXBElement<T>(new QName(clazz.getSimpleName()), clazz, object);
    JAXBSource source = new JAXBSource(jaxbContext, contentObject);
    return jaxbContext.createUnmarshaller().unmarshal(source, clazz).getValue();
  } catch (JAXBException e) {
      throw new RuntimeException(e);
  }
}

public static <T> T deepCopyJAXB(T object) {
  if(object==null) throw new RuntimeException("Can't guess at class");
  return deepCopyJAXB(object, (Class<T>) object.getClass());
}

它对我有用。

https://gist.github.com/darrend/821410

您可以使用JAXBSource

为同一类型创建2个JAXBContext:

JAXBContext sourceJAXBContext = JAXBContext.newInstance("Foo.class");
JAXBContext targetJAXBContext = JAXBContext.newInstance("Foo.class");

然后做:

targetJAXBContext.createUnmarshaller().unmarshal(
  new JAXBSource(sourceJAXBContext,sourceObject);

Object obj = ...  // object to copy

ObjectOutputStream out = new ObjectOutputStream(new ByteArrayOutputStream());
out.writeObject(obj);
byte[] bytes = baos.toByteArray();

ObjectInputStream in = new ObjectInputStream(new ByteArrayInputStream(bytes));
Object copy = in.readObject();

您可以使用XSD中的注释为生成的jaxb对象声明基类。。。

<xsd:annotation>
  <xsd:appinfo>
    <jaxb:globalBindings>
      <xjc:superClass name="com.foo.types.support.JaxbBase" />
    </jaxb:globalBindings>
  </xsd:appinfo>
</xsd:annotation>

您可以使用xmlbeans基类作为模板添加可克隆性支持。