如何从具有最高值的无序_映射中获取密钥?

我有以下代码,用于查看键是否存在,如果存在,则返回键和值:

std::unordered_map<std::string, int64_t> id_to_last_observation({
        {"apple", 10},
        {"lily", 12},
        {"avocado", 2},
        {"derry", 5},
        {"elephant", 13},
        {"monkey", 33},
        {"pineapple", 555}, 
        {"car", 1},
        {"ireland", 67},
        {"family", 48},
        {"laptop", 4},
        {"ladder", 90}, // element that begins with l that has the highest value
        {"computer", 98},
        {"travel", 99},
        {"orchestra", 65},
        {"party", 16},
        {"cube", 5}, 
        {"roller-coaster", 8},
        {"snake", 0},
        {"map", 11},
        {"umbrella", 51},
        {"lock", 47},
        {"person", 92},
        {"phone", 89},
        {"pen", 81},
    });

    std::unordered_map<std::string, int64_t>::iterator it;

    it = id_to_last_observation.find("ladder");

    if (it != id_to_last_observation.end()){
        std::cout << "Element Found - ";
        std::cout << it ->first<< "::" << it->second<< std::endl;
    }else{
        std::cout << "Element Not Found" << std::endl;
    }return 0;

然而,我在这里是手工操作的。我想做的是得到一个元素,它以我想要的任何字母开头,并且具有我想要的任何值(最高值、最低值等)。所以如果我想要以 l 在所有以 ,我想回去 ladder .

有没有一种方法可以在不使用暴力的情况下有效地做到这一点?