是否有更简洁的方法来获取相应的字典值

你可以通过做以下事情来减少一点:

try:
  print(pets[input("Enter pet name: ")])
  exit(0)
except KeyError:
  print("Pet not found, let's try a different one?")

这会在字典中显式查找输入“key”,并打印值并退出。如果密钥不存在,它会捕获错误并打印消息。

如果你不需要 exit 通过这种方式,它可以变得更短 get 返回默认消息:

print(pets.get(input("Enter pet name: "), "Pet not found, let's try a different one?")

对字典项进行迭代以查找关键字违背了字典的原则,效率非常低。只需直接访问它:

pets = {'bird': 3.5, 'cat': 5.0, 'dog': 7.25, 'gerbil': 1.5}

while True:

    req_pet = input("Enter pet name: ")

    if req_pet in pets:
        print(pets[req_pet])
        exit(0)
    else:
        print("Pet not found, let's try a different one?")