如果python迭代器返回iterable对象,如何将这些对象链接到一个大型迭代器中?

你可以用 itertools.chain.from_iterable

>>> import itertools
>>> x = iter([ xrange(0,5), xrange(5,10)])
>>> a = itertools.chain.from_iterable(x)
>>> list(a)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

如果您的版本上没有这个功能(显然,它是2.6中的新功能),您可以手动完成:

>>> x = iter([ xrange(0,5), xrange(5,10)])
>>> a = (i for subiter in x for i in subiter)
>>> list(a)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

这是老式的方法:

Python 2.2.3 (#42, May 30 2003, 18:12:08) [MSC 32 bit (Intel)] on win32
Type "help", "copyright", "credits" or "license" for more information.
>>> from __future__ import generators
>>> def mychain(iterables):
...     for it in iterables:
...         for item in it:
...             yield item
...
>>> x = iter([ xrange(0,5), xrange(5,10)])
>>> a = mychain(x)
>>> list(a)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>>

我不确定使用的目的或好处 iter() 在这种情况下:

>>> x = [xrange(0,5), xrange(5,10)]
>>> a = mychain(x)
>>> list(a)
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>>>