Python数据帧通过列获取零段的边框

我是用 more_itertools 考虑到 s

import more_itertools as mit
a = [list(group) for group in mit.consecutive_groups(s.loc[s.eq(0)].index.tolist())]

其次,从列表中选择第一个和最后一个条目

list(set([i[0] for i in a]+[x[-1] for x in a]))
#[3, 5, 8, 12, 15]

要获取0大于3的第一个和最后一个索引,请使用:

list(set([i[0] for i in a if len(i)>3]+[x[-1] for x in a if len(x)>3]))
#[8, 12]

s = [3,7,8,0,0,0,6,12,0,0,0,0,0,8,5,0,2]
idx = []
for i in range(len(s)):
    if s[i] == 0 and (s[i+1] != 0 or s[i-1] != 0):
        idx.append(i)
print (idx)
# result :[3, 5, 8, 12, 15]

entryFlag

s = [3,7,8,0,0,0,6,12,0,0,0,0,0,8,5,0,2]
entryFlag=True
i=0
s2=[]
for x in s:

    if entryFlag:
        if x==0:
            s2.append(i)
            entryFlag=False
    else:
        if x!=0:
            s2.append(i-1)
            entryFlag=True
    i+=1
print(s2)