将可变模板传递给pthread\u create

我明白 pthread_create 接受 void*(*)(void*) 论元与a void* ,因此我尝试了2次(失败)包装函数和参数…:

答。创建C样式 void *run(void*) 调用 std::function 传递给它的对象:

class thread
{
public:
    typedef std::function<void()> functor_t;

    static void* run(void* f) 
    {
        functor_t* functor = (functor_t*)f;
        (*functor)();
        delete functor;
        return nullptr;
    }

    template<typename Callable, typename... Args>
    explicit thread(size_t stack_size, Callable && callable, Args&&... args) {
        auto task_ptr = std::make_shared<std::packaged_task<decltype(callable(args...))()>>(
            std::bind(std::forward<Callable>(callable), std::placeholders::_1, std::forward<Args>(args)...)
            );
        functor_t* functor = new functor_t([task_ptr]() {
            (*task_ptr)();
        });

        pthread_attr_t attr = { 0};
        if (pthread_attr_init(&attr) == 0)
        {
            m_joinable = pthread_attr_setstacksize(&attr, stack_size) == 0 &&
                         pthread_create(&m_id, &attr, &run, functor);
            pthread_attr_destroy(&attr);
        }
    }
private:
    pthread_t   m_id        = -1    ;
    bool        m_joinable  = false ;
};

这导致GCC 4.8.5中出现以下错误:

/usr/include/c++/4.8.2/functional:在结构的实例化中 标准::绑定\u简单(标准::占位符<1>,int))(int*)>>()>: /usr/include/c++/4.8.2版本/future:1284:55:无效时需要 标准::\未来\基础::\任务\状态<_Fn,\u Alloc,\u Res(\u Args) …)>::_M_run(_Args…)[带_Fn=std::_Bind(std::_Placeholder<1>,int))(int*)>_Alloc=std::分配器; _Res=无效_Args={}]线程。cpp:17:1:此处需要/usr/include/c++/4.8.2/functional:1697:61:错误:没有名为type的类型 类内std::结果(std::占位符<1>,int))(int*)>>()&燃气轮机; ^/usr/include/c++/4.8.2/functional:1727:9:错误:没有名为type的类型 _M\u invoke(\u Index\u tuple<_索引…>) ^

http://coliru.stacked-crooked.com/a/a6c607514601b013

class thread
{
public:
    template< typename Callable, typename... Args >
    explicit thread(size_t stack_size, Callable&& callable, Args&&... args )
    {
        auto l = new auto([=]{ callable(args...); });
        auto te = [](void* rp) -> void*
        {
            auto p = reinterpret_cast<decltype(l)>(rp);
            (*p)();
            delete p;
            return nullptr;
        };
        pthread_attr_t attr = { 0};
        if (pthread_attr_init(&attr) == 0)
        {
            m_joinable = pthread_attr_setstacksize(&attr, stack_size) == 0 &&
                         pthread_create(&m_id, &attr, te, l);
            pthread_attr_destroy(&attr);
        }
    }
private:
    pthread_t   m_id        = -1    ;
    bool        m_joinable  = false ;
};

本应在叮当声中工作,但在GCC 4.8.5中失败:

在线程包含的文件中。cpp:2:0: thread.h:在lambda函数中: thread.h:82:37:错误:参数 auto l=new auto([=]{callable(args…);}); ^螺纹h:82:37:注:
args线程。h:82:41:错误: 扩展模式参数不包含参数包 auto l=new auto([=]{callable(args…);}); struct thread::线程(大小、可调用和&,参数(&A)&…)[具有 )(内景) ); Args={int*};size\u t=长无符号 int]::uu lambda4:线程。h:82:48:
thread::thread(size\u t,Callable&&,参数(&A)&…) [带Callable=void( )(内景) [int]线程。cpp:14:32:此处需要 无效的字段thread::thread(size\u t,Callable&&,参数(&A)& …)::\u lambda4::\u args ^thread.h:83:被前面的搞糊涂了 错误,退出

两者都有以下主要特点:

int g=5;

void run(int *i)
{
    printf("t\n");
}

int main()
{

    gs_thread t(256*1024, &run, &g);
    printf("m\n");
    t.join();
}