比较列表中的值以创建字典?

我正试图根据if条件将我的列表附加到字典中。我为这个问题写了一个工作函数,但我想把这个程序写在 列表理解 .

下面的函数按月份组织所有跟踪。结果将是一个以月份为键、以轨迹为值的字典。

[[j for j in lst2] for i in month if j[-2] == i] 
#I tried this list comprehension code for my function given below

列名
[位置,曲目名称,艺术家,流,datetime.object,区域,月,日]

 Input : #my working code

[['1','Starboy','The Weeknd','3135625',datetime.datetime(2017, 1, 1, 0, 0),
  'global',1,1],
 ['2','Closer','The Chainsmokers','3015525',datetime.datetime(2017, 1, 1, 0, 0),
  'global',1,1]
 ['3','Party Monster','The Weeknd','829599',datetime.datetime(2017, 2, 2, 0, 0),
'  global',2,2]]

def organized(lst2):
    month = [1,2]
    edict = {}
    for i in month:
        elst = []
        for j in lst2:
            if j[-2] == i:
                elst.append(j)
        edict[i] = elst
    return edict

output

{1: [['1', 'Starboy', 'The Weeknd', '3135625',
        datetime.datetime(2017, 1, 1, 0, 0),'global', 1, 1],
     ['2', 'Closer', 'The Chainsmokers', '3015525',                        
        datetime.datetime(2017, 1, 1, 0, 0), 'global', 1, 1]]
 2:[[‘3’, 'Party Monster', 'The Weeknd', '829599',
        datetime.datetime(2017, 2, 2, 0, 0), 'global', 2, 2]]}