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打印空金字塔

ascii-art python-3.x python

0

AHF · 技术社区 · 7 年前

   *
  * *
 *   *
*     *
   *

    * 
   * * 
  * * * 
 * * * * 
* * * * *

N

对于其余的星星,我不知道如何制作,如果一颗星星在上面,那么下一颗星星就不应该在下面。

def Empty_triangle(n): 
    k = 2*n - 2
    for i in range(0, n): 
        for j in range(0, k): 
            print(end=" ")

        k = k - 1

        for j in range(0, i+1): 
            # printing stars 
            print("* ", end="") 

        # ending line after each row 
        print("\r") 

# Driver Code 
n = 5
Empty_triangle(n)

1 回复 | 直到 7 年前

1

Morgan Saville 7 年前

这类事情怎么样?

print("\n".join([" "*(n-2-i)+"*"+" "*(2*i-1)+("*"if i>0 else"") for i in list(range(n-1))+[0]]))

   *
  * *
 *   *
*     *
   *

这就是你的想法吗?

这是一个代码较少的golfish版本

def Empty_triangle(n): 
    for i in list(range(n-1))+[0]: #i.e. [0,1,2,3,4,0] so the last line is the same as the first
        line = ""
        leadingSpaces = n-2-i
        line += " "*leadingSpaces
        line += "*"
        if i != 0:
            middleSpaces = 2*i-1
            line += " "*middleSpaces
            line += "*"
        print(line)


# Driver Code 
n = 5
Empty_triangle(n)