Python 3.x版function:Converting string 列出并打印排除某些字符的输出

首先将句子拆分为单词,然后迭代单词以重建(在内部循环中)修改的单词和(在外部循环中)单词列表:

def func():

    characters = '?/><,.:;"[]{}=+()*&^%$#@!' # keeping ' and -
    new_lst = []
    user = input("String: ")
    for word in user.split():
        x = ''
        for i in word:
            if (i not in characters):
                x += i # I know this is the problem but I just don't know where to go from here
        new_lst.append(x)

    print(new_lst)

func()

['Keep', 'hyphen-', 'and', "apostrophe's", 'only']

这不一定是一个代码审查网站,但我肯定会考虑更有效地命名变量,并对内部循环使用列表理解:

def get_stripped_word_list(s):
    """Return a list of words in string s, excluding certain characters."""

    # Sequence of characters to strip, keeping ' and -
    characters = '?/><,.:;"[]{}=+()*&^%$#@!'
    words = s.split()
    modified_words = []
    for word in words:
        modified_word_letters = [c for c in word if c not in characters]
        modified_words.append(''.join(modified_word_letters))
    return modified_words

s = input("String: ")
print(get_stripped_word_list(s))

可以替换字符,也可以拆分字符

def func():

    characters = '?/><,.:;"[]{}=+()*&^%$#@!' # keeping ' and -
    user = raw_input("String: ")
    for i in characters:
        user=user.replace(i,"")
    new_lst=user.split(" ")
    new_lst = [i.strip('.') for i in new_lst]
    print(new_lst)
func()

输出

['Keep', 'hyphen-', 'and', "apostrophe's", 'only']

你可以用 sub 从 re 模块:

import re
string = "Keep. hyphen- and apostrophe's only."

re.sub("[^\w '-]", '', string).split()

Out[672]: ['Keep', 'hyphen-', 'and', "apostrophe's", 'only']