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Spring-通过异常处理程序截获来自另一个bean的响应

exception-handling spring java

ByeBye · 技术社区 · 7 年前

@RestController s-(A和B)和注册 ResponseEntityExceptionHandler A 并得到 B 在应用异常处理程序之后?

用户rest调用
A B类 getPerson
B类 引发异常 NotFound
找不到 由异常处理程序处理,转换 ResponseEntity
B类 最终返回异常 反应性
A 从中获取状态 B类
A 你能拿这400块做点什么吗

@Autowired 不起作用。

代码段:

答:

@RestController
@RequestMapping("/v1")
public class A {

    private final B b;

    @Autowired
    public A(B b) {
        this.b = b;
    }

    @PostMapping(
        value = "persons",
        consumes = "application/json",
        produces = "application/json")
    public ResponseEntity<List<StatusResponse<Person>>> addPersons(final List<Person> persons) {
        final List<StatusResponse<Person>> multiResponse = new ArrayList<>();
        for(final Person p: persons) {
            final ResponseEntity<Person> response = b.addPerson(person);
            multiResponse.add(new StatusResponse<>(
                response.getStatusCode(), response.getMessage(), response.getBody()
            ));
        }
        return ResponseEntity.status(HttpStatus.MULTI_STATUS).body(multiResponse);
    }

}

@RestController
@RequestMapping("/v1")
public class B {

    @PostMapping(
        value = "person",
        consumes = "application/json",
        produces = "application/json")
    public ResponseEntity<Person> addPerson(final Person person) {
        accessService.checkAccess();
        return ResponseEntity.status(201).body(
            logicService.addPerson(person)
        );
    }

}

处理程序

@ControllerAdvice
public final class MyExceptionHandler extends ResponseEntityExceptionHandler {

    @ExceptionHandler(MyException.class)
    protected ResponseEntity<Object> handleApiException(final MyException exception, final WebRequest webRequest) {
        //logic
        return afterLogic;
    }

}

2 回复 | 直到 7 年前

ByeBye 7 年前

你的电流是这样的 call A.addPersons invoke B.addPerson -&燃气轮机; B throws exception -&燃气轮机; exception is propagate to A controller

我不确定在控制器中出现此异常时要执行什么操作,但解决方案可能如下所示:

@RestController
@RequestMapping("/resources")
public class AController {

    private BService service;

    @Autowired
    public AController(BService service) {
        this.service = service;
    }

    @RequestMapping("/test")
    public ResponseEntity<String> test() {
        ResponseEntity<String> result = service.test();
        if (result.hasBody()) {
            //doSomething
        }

        return result; //or list like you did
    }
}

@Service
public class BService {

    public ResponseEntity<String> test() {
        try {
            return ResponseEntity.status(201).body(getResponse()); //this always throws exception. It's just for purpose of example
        } catch (CustomException ex) {
            return ResponseEntity.status(400).build();
        }

    }

    private String getResponse() {
        throw new CustomException("Not OK!");
    }
}

Danial Jalalnouri 7 年前

forward类似于重定向,但完全发生在服务器端;Servlet容器将相同的请求转发到目标URL;URL在浏览器中不会更改。在spring中,可以这样做,并且可以传递属性:

@Controller
@RequestMapping("/")
public class YourController {

    @GetMapping("/forward")
    public ModelAndView redirectWithUsingForwardPrefix(ModelMap model) {
        model.addAttribute("attribute", "forward");
        return new ModelAndView("forward:/redirectedUrl", model);
    }
}