C++获取std::out\u of\u range异常的位置

有几种方法。

1. 正如您所说,调试器——但一旦代码投入生产,它就帮不了您。

2. 嵌套异常和函数try块。e、 g.:

#include <exception>
#include <stdexcept>
#include <iostream>
#include <sstream>
#include <iomanip>

void bar(std::string& s, int i)
try
{
    s.at(i) = 'A';
}
catch(...)
{
    std::ostringstream ss;
    ss << "error in bar(" << std::quoted(s) << ", " << i << ")";
    std::throw_with_nested(std::runtime_error(ss.str()));
}

void foo(std::string& s)
try
{
    bar(s, 6);
}
catch(...)
{
    std::ostringstream ss;
    ss << "error in foo(" << std::quoted(s) << ")";
    std::throw_with_nested(std::runtime_error(ss.str()));
}

void stuff()
try
{
    std::string s;
    foo(s);
}
catch(...)
{
    std::throw_with_nested(std::runtime_error("error in stuff()"));
}

void print_exception(std::ostream& os, const std::exception& e, int level =  0)
{
    os << std::string(level, ' ') << "exception: " << e.what() << '\n';
    try {
        std::rethrow_if_nested(e);
    } catch(const std::exception& e) {
        print_exception(os, e, level+1);
    } catch(...) {}
}

int main()
{
    try{
        stuff();
    }
    catch(std::exception& e)
    {
        print_exception(std::cerr, e);
        return 127;
    }
    return 0;
}

示例输出:

exception: error in stuff()
 exception: error in foo("")
  exception: error in bar("", 6)
   exception: basic_string::at: __n (which is 6) >= this->size() (which is 0)

3. 你可以使用 boost::stacktrace 代替上述嵌套的异常处理。

http://coliru.stacked-crooked.com/a/f21bd35632a0a036