如何在文本文件中逐行打印数组的内容?

您可以使用更多的pythonic方法来实现所需的输出。

file.writelines('\n'.join(applicants))

你的错误/问题在你的逻辑中,特别是在你的else块中。
对于 大卫 您的索引是 1 所以它将进入 else 其他的 阻止您将行写为 el+"\n" 所以 David 正在与添加到同一行 Avery 然后添加新行。我希望这消除了你的疑虑。所以如果在 其他的 file.write("\n"+el) 并且在 elif 也

另一种方法可以是:-

with open("Fiddle.txt","w") as file:
    file.writelines("\n".join(applicants)) # will join elements of list with "\n"

将在新行上打印姓名。

您只需在每行的开头而不是末尾打印换行符。这样你就不需要解释最后一行了! 您还可以避免索引的递增。

for el in applicants:  # write the name of the worker to the text file
    if index == 0:  # this is the first line no need for a line break
        file.write(el)
        # increment the index for later iterations
        index += 1
    else:  # these are the middle lines and it is essential to break a line
        file.write("\n"+el)

applicants = ["Timothy", "David", "Mary", "Drew", "Titus", "Samuel","Avery"]
# sort the names of the applicants
applicants.sort()

with open("sample.txt", "w+") as f:
    for name in applicants:
        f.write(str(name) + "\n")