读取字符串直到标志(C++)

尝试以下操作:

std::size_t pos = coorPair.find_first_of(","); //Find position of ','
xCoor = coorPair.substr(0, pos); //Substring x position string
yCoor = coorPair.substr(pos + 1); //Substring y position string
int xCoorInt = std::stoi(xCoor); //Convert x pos string to int
int yCoorInt = std::stoi(yCoor); //Convert y pos string to int

operator>> 为您完成所有工作:

int xCoor, yCoor;
char ch;

cout << "Input coordinates: ";

if (cin >> xCoor >> ch >> yCoor)
{
    // use coordinates as needed ...
}
else
{
    // bad input... 
}

可以通过指定分隔符并解析字符串来实现这一点

std::string delimiter = ",";

size_t pos = 0;
std::string token;
while ((pos = coorPair.find(delimiter)) != std::string::npos) {
    token = coorPair.substr(0, pos);
    std::cout << token << std::endl;
    coorPair.erase(0, pos + delimiter.length());
}

std::cout << coorPair << endl;

{5,6}中的最后一个令牌示例{6}将位于coorPair中。

std::getline 正如评论中指出的那样:

std::string token; 
while (std::getline(coorPair, token, ',')) 
{ 
    std::cout << token << std::endl; 
}

http://www.cplusplus.com/reference/string/string/getline/

下面是我如何使用它的一个小例子。它从流中获取输入,因此您可以使用ifstream作为输入,也可以像我下面所做的那样将字符串转换为流。

// input data
std::string data("4,5,6,7,8,9");

// convert string "data" to a stream
std::istringstream d(data);

// output string of getline()
std::string val;

std::string x;
std::string y;
bool isX = true;

char delim = ',';

// this will read everything up to delim
while (getline(d, val, delim)) {
    if (isX) {
        x = val;
    }
    else {
        y = val;
    }
    // alternate between assigning to X and assigning to Y
    isX = !isX;
}