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角度2如何将两个相等的索引数组合并为一个?

typescript angular javascript

-2

Angulandy2 · 技术社区 · 7 年前

A [
{name: Jhon}
{name: Jacob}
{name: Lukas}
]

B [
{fr: Prince} //fr, en, it is language, Prince is LastName
{en: Breed}
{it: Lasontos}
]

如何将其合并为一个,使其看起来像这样:

 A [
    {name: Jhon, lastname: Prince, country: fr }
    {name: Jacob, lastname: Breed, country: en}
    {name: Lukas, lastname: Lasontos, country: it}
    ]

3 回复 | 直到 7 年前

1

5

Andrei Todorut 7 年前

使用 Object.assign(obj1, obj2) 和 map() 方法应用于第一个对象数组。

var arr = [
  {firstname: 'John'},
  {firstname: 'Hello'}
]

var arr2 = [
  {fr: 'Here'},
  {en: 'There'}
]

arr.map((obj, index) => {

  var internalization = {
    country: Object.keys(arr2[index])[0],
    lastname: arr2[index][Object.keys(arr2[index])[0]]
  }

  return Object.assign(obj, internalization);
})

console.log(arr);

工作小提琴:

https://jsbin.com/wepibuwazi/1/edit?js,console,output

2

1

rozza2058 7 年前

var A = [
  {name: Jhon}
  {name: Jacob}
  {name: Lukas}
]

var B = [
  {fr: Prince} //fr, en, it is language, Prince is LastName
  {en: Breed}
  {it: Lasontos}
]

A.map((obj, index) => {
  var keys = Object.keys(B[index]);
  obj.country = keys[0];
  obj.lastname = B[index][keys[0]];
  return obj;
});

3

0

Code Maniac 7 年前

你可以试试这个

let A = [
         {name: 'Jhon'},
         {name: 'Jacob'},
         {name: 'Lukas'}
        ]

let B = [
         {fr: 'Prince'},
         {en: 'Breed'},
         {it: 'Lasontos'},
        ]

 for(let i in B){
   let temp = Object.keys(B[i])[0];
   A[i].country = temp
   A[i].lastname = B[i][temp];
 }

console.log(A)