使用映射或理解列表python从全局变量创建字典列表

很确定你可以在一条丑陋的线里做到这一点。假设您使用不可变值,否则您必须进行深度复制,这也是可能的:

[GLOBAL.copy().update(second=w) for w in word]

[{**GLOBAL, "second": w} for w in word]

GLOBAL = {"first": "Won't change", "second": ""}
words = ["a", "test"]
result_list = []
for word in words:
    dictionary_to_add = GLOBAL.copy()
    dictionary_to_add["second"] = word
    result_list.append(dictionary_to_add)
print result_list
def hello(word):
    dictionary_to_add = GLOBAL.copy()
    dictionary_to_add["second"] = word
    return dictionary_to_add
print [hello(word) for word in words]
print map(hello,words)

测试它,并尝试更多。