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如何对变量中的整数排序?

python-3.3 python

-1

Anonymous · 技术社区 · 11 年前

请注意,这是在Python 3.3上

代码如下:

students=int(input("How many student's score do you want to sort? "))
options=input("What do you want to sort: [Names with scores] , [Scores high to low] , [Scores averages] ? ")
options=options.upper()

if options == ("NAMES WITH SCORES") or  options == ("NAME WITH SCORE") or  options == ("NAME WITH SCORES") or options == ("NAMES WITH SCORE"):
    a=[]
    for i in range(0,students):
        name=input("Enter your scores and name: ")
        a.append(name)

    a.sort()
    print("Here are the students scores listed alphabetically")
    print(a)

if options == ("SCORES HIGH TO LOW") or  options == ("SCORE HIGH TO LOW"):
    b=[]
    number=0
    for i in range(0,students):
        number = number+1
        print("Student "+str(number))
        name2=int(input("Enter your first score: "))
        name3=int(input("Enter your second score: "))
        name4=int(input("Enter your third score: "))

        b.append(name2)
        b.append(name3)
        b.append(name4)

    final_score = name2 + name3 + name4
    print (final_score)
    b.sort(final_score)
    print("Student "+str(number) )
    print(b)

以下是代码的结果:

>>> 
How many student's score do you want to sort? 2
What do you want to sort: [Names with scores] , [Scores high to low] , [Scores averages] ? scores high to low
Student 1
Enter your first score: 1
Enter your second score: 2
Enter your third score: 3
Student 2
Enter your first score: 3
Enter your second score: 5
Enter your third score: 6
14
Traceback (most recent call last):
  File "H:\GCSE Computing\Task 3\Task 3.py", line 31, in <module>
    b.sort(final_score)
TypeError: must use keyword argument for key function
>>>

我希望代码将学生的三个分数相加,并根据相应的名称对学生的总分进行排序。

例如: (2名学生)

学生1

得分1-2
得分2-4
得分3-7

(因此总数为13)

学生2

得分1-5
得分2-1
得分3-4

(因此总数为10)

(程序按从最高到最低的顺序打印)

“学生1-15,学生2-10”

1 回复 | 直到 11 年前

Padraic Cunningham 11 年前

你需要使用语法 key=final_score 传递排序依据的函数时:

b.sort(key=final_score)

但sort方法需要 function 要传递的不通过 int 添加的值 name2 + name3 + name4 不起作用。

如果您只想对分数列表进行排序,只需调用 b.sort()

你应该做的是使用默认字典,并使用每个名称作为关键字,并将所有分数存储在列表中:

from collections import defaultdict


d = defaultdict(list)

for _ in range(students):
    name = input("Enter your name: ")
    scores = input("Enter your scores separated by a space: "
    # add all scores for the user to the list
    d[name].extend(map(int,scores.split()))

要显示平均值、总值和最大值,这是微不足道的:

# from statistics import mean will work for python 3.4

for k,v in d.items():
       print("Scores total for {} is {}".format(k,sum(v)))
       print("Scores average for {} is {}".format(k,sum(v)/len(v))) # mean(v) for python 3,4
       print("Highest score  for {} is {}".format(k, max(v)))

按最高用户总分排序的打印:

print("The top scoring students from highest to lowest are:")
for k,v in sorted(d.items(),key=lambda x:sum(x[1]),reverse=True):
    print("{} : {}".format(k,sum(v)))

现在你有一个字典,其中学生的名字是关键,每个学生的分数都存储在一个列表中。

实际上,您应该添加一个try/except,接受用户输入并验证其格式是否正确。