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获取一个包含数组中所有对象键的数组

ecmascript-6 node.js arrays jquery javascript

Ankit Agarwal · 技术社区 · 6 年前

所以,我得到的是这样一个数组:

let record = [{
    "province": "string",
    "city": "string",
    "type": "alternative_address",
    "address_line1": "string",
    "post_code": "5858"
  },
  {
    "province": "string",
    "city": "string",
    "type": "alternative_address",
    "post_code": "5858",
    "embedeer": {
      "veryEmbedded": {
        "veryveryEmbeded": 'yes'
      }
    }
  }
];

通过一些计算,我期望输出如下:

['province','city','type','address_line1','post_code','embedeer', 'embedeer.veryEmbedded', 'embedeer.veryEmbedded.veryveryEmbeded'];

reduce() 对数组执行操作,但我无法获取。

4 回复 | 直到 6 年前

Nikhil Aggarwal 6 年前

您需要编写一个接受两个输入的递归函数

对象
前缀(未定义一级键)

let record = [{"province":"string","city":"string","type":"alternative_address","address_line1":"string","post_code":"5858"},{"province":"string","city":"string","type":"alternative_address","post_code":"5858","embedeer":{"veryEmbedded":{"veryveryEmbeded":"yes"}}}];

function addKeysToSet(o, p) {
  Object.keys(o).forEach(k => {
    let key = p ? p + "." + k : k; // Create the key hierarchy
    keys.add(key); // Add key to the set 
    // If the value is an object, call the function recursively 
    if(typeof o[k] === 'object') {
      addKeysToSet(o[k], key);
    }
  });
}

let keys = new Set(); // Create set of unique keys
// For each object in array, call function that adds keys to the set
record.forEach(o => addKeysToSet(o));
let result = Array.from(keys); // Create array from set
console.log(result); // logs result

Nina Scholz 6 年前

Set 为了得到独特的价值。

function iter(object, keys) {
    return Object
        .entries(object)
        .reduce((r, [k, v]) => r.concat(keys.concat(k).join('.'), v && typeof v === 'object'
            ? iter(v, keys.concat(k))
            : []
        ), []);        
}

var record = [{ province: "string", city: "string", type: "alternative_address", address_line1: "string", post_code: "5858" }, { province: "string", city: "string", type: "alternative_address", post_code: "5858", embedeer: { veryEmbedded: { veryveryEmbeded: 'yes' } } }],
    keys = [...record.reduce((s, o) => iter(o, []).reduce((t, v) => t.add(v), s), new Set)];

console.log(keys);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Jimish Fotariya 6 年前

// form https://gist.github.com/penguinboy/762197

let record = [{"province":"string","city":"string","type":"alternative_address","address_line1":"string","post_code":"5858"},{"province":"string","city":"string","type":"alternative_address","post_code":"5858","embedeer":{"veryEmbedded":{"veryveryEmbeded":"yes"}}}];

var flattenObject = function(a) {
  var b = {};
  for (var c in a)
    if (a.hasOwnProperty(c))
      if ("object" == typeof a[c]) {
        var d = flattenObject(a[c]);
        for (var e in d) d.hasOwnProperty(e) && (b[c + "." + e] = d[e]);
      } else b[c] = a[c];
  return b;
};

console.log(flattenObject(record) )

/*
 It is also taking care of index numbers of the array. ("0.province" instead of "province" If multiple entries are passed)  
 
 */
console.info( "All keys", Object.keys(flattenObject(record) ) )

// Simple
console.info( "keys", Object.keys(flattenObject(record[1]) ) )

Nishant Dongare 6 年前

var record1 = [{"province": "string","city": "string","type": "alternative_address","address_line1": "string","post_code": "5858" },
  { "province": "string","city": "string",
    "type": "alternative_address",
    "post_code": "5858",
    "embedeer": {
      "veryEmbedded": {
        "veryveryEmbeded": 'yes'
      }
    }
  }
];

var output = [];
function getAllKeys(obj,precedor="") {
  var temp = Object.entries(obj);
  temp.forEach((el) => 
               typeof el[1] == "object" ? ( output.push(el[0]),getAllKeys(el[1],precedor==""? el[0]: precedor+"."+el[0])): output.push(precedor==""? el[0]: precedor+"."+el[0]));
}
 record1.forEach((el,i) => getAllKeys(el,""));
//To avoid duplicate entries convert array to object.
console.log(...(new Set(output)));