代码之家 › 专栏 › 技术社区 › IAdapter

如何在Java的XPath中禁用运行时DTD?

doctype dtd xpath java

14

IAdapter · 技术社区 · 16 年前

文件里有DTD,我不能把它删除。当我试图在Java中解析它时,我会得到“Java.NET.SoCoCutExc:网络是不可达的:Connect”,因为它的远程DTD。我可以禁用DTD检查吗?

3 回复 | 直到 12 年前

1

18

Community CDub 8 年前

您应该能够指定自己的EntityResolver,或者使用解析器的特定功能?见 here 对于某些方法。

更完整的例子:

<?xml version="1.0"?>
<!DOCTYPE foo PUBLIC "//FOO//" "foo.dtd">
<foo>
    <bar>Value</bar>
</foo>

和xpath用法:

import java.io.File;
import java.io.IOException;
import java.io.StringReader;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathFactory;

import org.w3c.dom.Document;
import org.xml.sax.EntityResolver;
import org.xml.sax.InputSource;
import org.xml.sax.SAXException;

public class Main {

    public static void main(String[] args) throws Exception {
        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        DocumentBuilder builder = factory.newDocumentBuilder();

        builder.setEntityResolver(new EntityResolver() {

            @Override
            public InputSource resolveEntity(String publicId, String systemId)
                    throws SAXException, IOException {
                System.out.println("Ignoring " + publicId + ", " + systemId);
                return new InputSource(new StringReader(""));
            }
        });
        Document document = builder.parse(new File("src/foo.xml"));
        XPathFactory xpathFactory = XPathFactory.newInstance();
        XPath xpath = xpathFactory.newXPath();
        String content = xpath.evaluate("/foo/bar/text()", document
                .getDocumentElement());
        System.out.println(content);
    }
}

希望这有帮助…

2

14

David 15 年前

这对我很有用:

 SAXParserFactory saxfac = SAXParserFactory.newInstance();
  saxfac.setValidating(false);
  try {
    saxfac.setFeature("http://xml.org/sax/features/validation", false);
    saxfac.setFeature("http://apache.org/xml/features/nonvalidating/load-dtd-grammar", false);
    saxfac.setFeature("http://apache.org/xml/features/nonvalidating/load-external-dtd", false);
    saxfac.setFeature("http://xml.org/sax/features/external-general-entities", false);
    saxfac.setFeature("http://xml.org/sax/features/external-parameter-entities", false);
  }
  catch (Exception e1) {
    e1.printStackTrace();
  }

3

2

Owen 16 年前

我以前有过这个问题。我通过下载和存储DTD的本地副本,然后根据本地副本进行验证,解决了这个问题。您需要编辑XML文件以指向本地副本。

<!DOCTYPE root-element SYSTEM "filename">

这里有更多信息: http://www.w3schools.com/dtd/dtd_intro.asp

我认为您还可以在解析器中手动将某种validateOnParse属性设置为“false”。取决于您用来解析XML的库。

更多信息在这里: http://www.w3schools.com/dtd/dtd_validation.asp