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Typescript/lodash:如何获得具有多个公共属性的结果/对象

lodash group-by filter typescript javascript

SatAj · 技术社区 · 6 年前

我正在为具有多个属性的groupBy函数寻找lodash/typerscript解决方案。以下是我迄今为止尝试过的:

JSON码:

[
    {
        "jobId": 1001,
        "id": 1,
        "timeSegmentId": 1,
        "balance": 100
    },
    {
        "jobId": 1001,
        "id": 2,
        "timeSegmentId": 1,
        "balance": 100
    },
    {
        "jobId": 1002,
        "id": 1,
        "timeSegmentId": 1,
        "balance": 100
    },
    {
        "jobId": 1002,
        "id": 1,
        "timeSegmentId": 1,
        "balance": 100
    },
    {
        "jobId": 1003,
        "id": 1,
        "timeSegmentId": 1,
        "balance": 100
    },
    {
        "jobId": 1003,
        "id": 1,
        "timeSegmentId": 2,
        "balance": 100
    },
    {
        "jobId": 1003,
        "id": 1,
        "timeSegmentId": 2,
        "balance": 100
    },
    {
        "jobId": 1003,
        "id": 1,
        "timeSegmentId": 2,
        "balance": 100
    },
    {
        "jobId": 1003,
        "id": 1,
        "timeSegmentId": 2,
        "balance": 100
    }
]

Typescript代码:

  // Group of same ids
  let mergeResults = _.groupBy(this.BSSDealresults, function (n) {
     return n.timeSegmentId;
  });
  const objKeys = Object.keys(mergeResults);
  const AggregateResults = [];
  objKeys.forEach(item => {
    if (mergeResults[item].length > 1) {

      let agg_balance = 0;

      mergeResults[item].forEach(element => {
        agg_balance += element.balance;
      });
      AggregateResults.push({
        id: mergeResults[item][0].id,
        jobId: mergeResults[item][0].jobId,
        balance: agg_balance
      });
    } else {
      AggregateResults.push(mergeResults[item][0]);
    }
  })

然而,我正在寻找基于多个属性的聚合结果,例如id、jobId和timeSegId。

在lodash/typescript中,有没有什么方法可以通过使用多个属性来应用程序?

预期输出应为:

[
    {
        "jobId": 1001,
        "id": 1,
        "timeSegmentId": 1,
        "balance": 100
    },
    {
        "jobId": 1001,
        "id": 2,
        "timeSegmentId": 1,
        "balance": 100
    },
    {
        "jobId": 1002,
        "id": 1,
        "timeSegmentId": 1,
        "balance": 200
    },
    {
        "jobId": 1003,
        "id": 1,
        "timeSegmentId": 1,
        "balance": 100
    },
    {
        "jobId": 1003,
        "id": 1,
        "timeSegmentId": 2,
        "balance": 100
    },
    {
        "jobId": 1003,
        "id": 1,
        "timeSegmentId": 2,
        "balance": 300
    }
]

1 回复 | 直到 6 年前

Ori Drori 6 年前

_.groupBy() 通过从3个ID中创建一个字符串。那你就可以了 _.map() 小组 BSSDealresults 对象,使用 object spread (或 Object.assign() _.sumBy()

const BSSDealresults = [{"jobId":1001,"id":1,"timeSegmentId":1,"balance":100},{"jobId":1001,"id":2,"timeSegmentId":1,"balance":100},{"jobId":1002,"id":1,"timeSegmentId":1,"balance":100},{"jobId":1002,"id":1,"timeSegmentId":1,"balance":100},{"jobId":1003,"id":1,"timeSegmentId":1,"balance":100},{"jobId":1003,"id":1,"timeSegmentId":2,"balance":100}];

const mergeResults = _.groupBy(BSSDealresults, ({ id, jobId, timeSegmentId }) => `${id}-${jobId}-${timeSegmentId}`);

const AggregateResults = _.map(mergeResults, group => ({
  ...group[0],
  balance: _.sumBy(group, 'balance')
}));

console.log(AggregateResults);

<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.11/lodash.min.js"></script>