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在python中,通过将类方法的方法名保存在for循环的var中来连接到类方法

pyqt4 pyqt python-3.x python-2.7 python

Nestor Colt · 技术社区 · 8 年前

PyQt4 在同一个函数中,此函数将查找 按钮名称或标题 和a 班管理不同操作的实例方法名称。

班 instance methods 方法 callback() 无论如何。

##############################################
# Operatios RIG class INSTANCE
#
self.OperationsRig = OperationsFile.Operations()
#### BUTTONS TO CONNECT -----------------------#

mirrorButton.clicked.connect(self.operations_module)
flipButton.clicked.connect(self.operations_module)
resetButton.clicked.connect(self.operations_module)
visibilityButton.clicked.connect(self.operations_module)

def operations_module(self):
    # Text gives me the name to Match ------------------#
    text = self.sender().text()
    # ------------------------#
    # have 3 ways of getting the class instance methods into a list to iterate ..
    method_list = [func for func in dir(self.OperationsRig) if callable(getattr(self.OperationsRig, func))]
    methods = vars(self.OperationsRig.__class__).items()
    member =inspect.getmembers(self.OperationsRig, predicate=inspect.ismethod)

    # This var is a list to pass to the Method
    Sel_list = cmds.ls(sl=True)

    # iterate over the "self.OperationsRig" methods
    #
    """ option 1 """
    for meth in method_list:
        if text.strip().lower() in meth.lower()[:]:
            # if match, and it does, will call the class method and send the data.
            pass
            #getattr(self.OperationsRig,meth)(Sel_list)  # Executes the funcion instance, but is not
                                                         # sending the data, I've checked printing inside.
                                                         # NoneTypeObject is not iterable. no data sent.

    """ option 2 """
    for meth in methods:
        if text.strip().lower() in meth[0].lower()[:]:
            pass
            # if match, and it does, will call the class method and send the data.
            #method = meth[1]   # Gets the memory address of the function. Good.
            #method(Sel_list)   # Does not return anything, the process of the funcion gets an
                                # error at the very beggining of the method process

    """ option 3 """
    for meth in member:
        if text.strip().lower() in meth[0].lower()[:]:
            meth[1](Sel_list)  # Gets the memory address of the function. Good. as a bound method
                               # Same result as option 1 - # NoneTypeObject is not iterable. no data sent.
# --------------------------------------------------------------------------------------------------#

匹配进行得很好,问题是调用函数。我做错了什么?

1 回复 | 直到 8 年前

kesumu 8 年前

我不知道OperationsRig类的定义,所以我自己定义了一个。

因为它可以成功匹配,我认为这不是pyqt的问题。

这是我的代码:

class OperationsRig:
    def foo(self, msg):
        print('foo:' + str(msg))
        return 'foo OK'

    def foo1(self, msg):
        print('foo1:' + str(msg))
        return 'foo1 OK'


opr = OperationsRig()

def operations_module(text):
    # Text gives me the name to Match ------------------#
    # ------------------------#
    # have 3 ways of getting the class instance methods into a list to iterate ..
    method_list = [func for func in dir(opr) if callable(getattr(opr, func))]

    # This var is a list to pass to the Method
    Sel_list = [1,2,3]

    # iterate over the "self.OperationsRig" methods
    #
    """ option 1 """
    for meth in method_list:
        if text.strip().lower() in meth.lower()[:]:
            # if match, and it does, will call the class method and send the data.
            pass
            return getattr(opr, meth)(Sel_list)  # Executes the funcion instance, but is not
                                                         # sending the data, I've checked printing inside.
                                                         # NoneTypeObject is not iterable. no data sent.
print(operations_module('foo'))
print(operations_module('foo1'))

结果如下:

foo:[1, 2, 3]
foo OK
foo1:[1, 2, 3]
foo1 OK

Process finished with exit code 0

正如我所期望的那样,我仍然不明白为什么你的代码失败了。或者你可以做进一步的解释。