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python中逻辑语句的组合(and、or)

logic tkinter python

Adrian DSouza · 技术社区 · 7 年前

我目前正在tkinter制作一个石头、布、剪刀射击游戏,并试图编写一个函数来决定谁获胜。1=石头,2=布,3=剪刀。脚本不会打印任何内容,除非comp==2且choice==1。

def Winning():
    if (((comp == 2) and (choice == 1)) or ((comp == 3) and (choice == 2)) or
        ((comp == 1) and (choice == 3))):
        messagebox.showinfo("Info", "YOU LOSE!!!")
    if (((choice == 2) and (comp == 1)) or ((choice == 3) and (comp == 2)) 
      or ((choice == 1) and (comp == 3))):
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "DRAW!!!")

2 回复 | 直到 7 年前

cdlane 7 年前

我认为你走错了方向。假设我们必须使用数字输入,我会:

ROCK, PAPER, SCISSORS = range(1, 4)

roshambo = {
    ROCK: SCISSORS,
    PAPER: ROCK,
    SCISSORS: PAPER
}

def Winning(comp, choice):
    if comp == choice:
        messagebox.showinfo("Info", "DRAW!!!")
    elif comp == roshambo[choice]:
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "YOU LOSE!!!")

这使您的逻辑清晰,并简化了代码。而且,它更容易扩展问题:

ROCK, PAPER, SCISSORS, LIZARD, SPOCK = range(1, 6)

roshambo = {
    ROCK: [LIZARD, SCISSORS],
    PAPER: [ROCK, SPOCK],
    SCISSORS: [PAPER, LIZARD],
    LIZARD: [SPOCK, PAPER],
    SPOCK: [SCISSORS, ROCK]
}

def Winning(comp, choice):
    if comp == choice:
        messagebox.showinfo("Info", "DRAW!!!")
    elif comp in roshambo[choice]:
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "YOU LOSE!!!")

字典是你的朋友,没有字典就不要编程!

Paul 7 年前

您的函数从何处获取 comp 和 choice ?

像这样的方法会奏效:

from tkinter import messagebox

rock=1
paper=2
scissors=3


def Winning(comp, choice):
    if (((comp == 2) and (choice == 1)) or ((comp == 3) and (choice == 2)) or((comp == 1) and (choice == 3))):
        messagebox.showinfo("Info", "YOU LOSE!!!")
    if (((choice == 2) and (comp == 1)) or ((choice == 3) and (comp == 2)) or((choice == 1) and (comp == 3))):
        messagebox.showinfo("Info", "YOU WIN!!!")
    else:
        messagebox.showinfo("Info", "DRAW!!!")


Winning(rock, paper)

这就是你想要的吗?

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