如何在多词典列表中对词典的每个值进行模糊搜索?

你可以用这样的东西

>>> l = [
... {"Name":"Arnold", "Age":"52", "Height":"160"}, 
... {"Name":"Donald", "Age":"52", "Height":"161"}, 
... {"Name":"Trevor", "Age":"22", "Height":"150"}
... ]
>>>
>>> [d for d in l if any("nol" in v for v in d.values())]
[{'Age': '52', 'Name': 'Arnold', 'Height': '160'}]
>>>
>>> [d for d in l if any("52" in v for v in d.values())]
[{'Age': '52', 'Name': 'Arnold', 'Height': '160'}, {'Age': '52', 'Name': 'Donald', 'Height': '161'}]

这是我的版本,它不会同时将所有结果保存在列表中,而是根据需要生成结果。

import itertools

database = [
    {"Name":"Arnold", "Age":"52", "Height":"160"}, 
    {"Name":"Donald", "Age":"52", "Height":"161"}, 
    {"Name":"Trevor", "Age":"22", "Height":"150"},
]

def search(s):
    s = s.lower() # it is a nice feature to ignore case
    for item in database:
        if any(s in v.lower() for v in item.values()): # if any value contains s
            yield item # spit out the item — this is a generator function

# iterate over at most 5 first results
for result in itertools.islice(search("52"), 5):   
    print(result)

{'Height': '160', 'Age': '52', 'Name': 'Arnold'}
{'Height': '161', 'Age': '52', 'Name': 'Donald'}

另一个略有不同的选项:

searchTerm = "nol"
unusedCharacter = "\n"  # This should be a character that will never appear in your search string.
# Changed this to a generator to avoid searching the whole dict all at once:
results = (d for d in l if searchTerm in unusedCharacter.join(d.values()))

# Produce a limited number of results:
limitedResults = []
maxResults = 5
for k, result in enumerate(results):
    if k == maxResults:
        break
    limitedResults.append(result)