代码之家 › 专栏 › 技术社区 › Pyd

在python中为列表中的项目生成词云

word-cloud word list string python

15

Pyd · 技术社区 · 7 年前

 my_list=["one", "one two", "three"]

 wordcloud = WordCloud(width = 1000, height = 500).generate(" ".join(my_list))

当我将所有项目转换为字符串时,它正在为

   "one","two","three"

 But I want to generate word cloud for the values, "one","one two","three"

2 回复 | 直到 7 年前

1

16

Pyd 4 年前

一种方法,

import matplotlib.pyplot as plt
from wordcloud import WordCloud

#convert list to string and generate
unique_string=(" ").join(my_list)
wordcloud = WordCloud(width = 1000, height = 500).generate(unique_string)
plt.figure(figsize=(15,8))
plt.imshow(wordcloud)
plt.axis("off")
plt.savefig("your_file_name"+".png", bbox_inches='tight')
plt.show()
plt.close()

#convert it to dictionary with values and its occurences
from collections import Counter
word_could_dict=Counter(my_list)
wordcloud = WordCloud(width = 1000, height = 500).generate_from_frequencies(word_could_dict)

plt.figure(figsize=(15,8))
plt.imshow(wordcloud)
plt.axis("off")
#plt.show()
plt.savefig('yourfile.png', bbox_inches='tight')
plt.close()

2

1

ikkuh 7 年前

这个 WordCloud 将正则表达式作为参数。使用这个,我们可以使分割字符 +

regexp=r"\w[\w' ]+"

然后需要将单词列表连接到 +

wordcloud = WordCloud(width=1000, height=500, regexp=r"\w[\w' ]+").generate("+".join(my_list))