我正在调试一个完整的内存转储(
procdump -ma ...
,我正在研究调用堆栈,对应于以下源代码:
unsigned int __stdcall ExecutionThread(void* pArg)
{
__try
{
BOOL bRunning = TRUE;
CInternalManagerObject* pInternalManagerObject = (CInternalManagerObject*) pArg;
pInternalManagerObject->Init();
CInternaStartlManagerObject* pInternaStartlManagerObject = pInternalManagerObject->GetInternaStartlManagerObject();
while(bRunning)
{
bRunning = pInternalManagerObject->Poll(pInternaStartlManagerObject);
if (CSLGlobal::IsValidHandle(_Module.m_hNeverEvent))
WaitForSingleObject(_Module.m_hNeverEvent, 15);
} <<<<<<<<<<<<<<<<============== here is the call stack pointer
pInternalManagerObject->DeInit();
正如你所看到的,
pArg
正在被打字然后被使用,所以这是不可能的
帕格
成为
NULL
但这正是观察窗告诉我的。除此之外,似乎不知道内部变量(也如观察窗口中所述)。
监视窗口内容:
pArg 0x0000000000000000 void *
bRunning identifier "bRunning" is undefined
pInternalManagerObject identifier "pInternalManagerObject" is undefined
我能理解
bRunning
被优化掉,因为这个变量不再被使用,但这不适用于
pInternalManagerObject
,在下面的行中仍然使用。
符号似乎加载得很好。
我使用Visual Studio Professional 2017版本15.8.8查看此。
有没有人知道是什么导致了这种奇怪的行为?我可以做些什么来获得一个内部变量值正确的转储文件?
生成的程序集代码的问题后编辑
生成的程序集是:
27:
28: unsigned int __stdcall ExecutionThread(void* pArg)
29: {
00007FF69C7A1690 48 89 5C 24 08 mov qword ptr [rsp+8],rbx
00007FF69C7A1695 48 89 74 24 10 mov qword ptr [rsp+10h],rsi
00007FF69C7A169A 57 push rdi
00007FF69C7A169B 48 83 EC 20 sub rsp,20h
00007FF69C7A169F 48 8B F9 mov rdi,rcx
30: __try
31: {
32: BOOL bRunning = TRUE;
00007FF69C7A16A2 BB 01 00 00 00 mov ebx,1
33: CInternalManagerObject* pInternalManagerObject = (CInternalManagerObject*) pArg;
34:
35: pInternalManagerObject->Init();
00007FF69C7A16A7 E8 64 EA FD FF call CInternalManagerObject::Init (07FF69C780110h)
36:
37: CBaseManager* pBaseManager = pInternalManagerObject->GetBaseManager();
00007FF69C7A16AC 48 8B CF mov rcx,rdi
00007FF69C7A16AF E8 0C E9 FD FF call CInternalManagerObject::GetBaseManager (07FF69C77FFC0h)
00007FF69C7A16B4 48 8B F0 mov rsi,rax
40: {
41: bRunning = pInternalManagerObject->Poll(pBaseManager);
00007FF69C7A16B7 48 8B CF mov rcx,rdi
38:
39: while(bRunning)
00007FF69C7A16BA 85 DB test ebx,ebx
00007FF69C7A16BC 74 2E je ExecutionThread+5Ch (07FF69C7A16ECh)
40: {
41: bRunning = pInternalManagerObject->Poll(pBaseManager);
00007FF69C7A16BE 48 8B D6 mov rdx,rsi
40: {
41: bRunning = pInternalManagerObject->Poll(pBaseManager);
00007FF69C7A16C1 E8 7A ED FD FF call CInternalManagerObject::Poll (07FF69C780440h)
00007FF69C7A16C6 8B D8 mov ebx,eax
42:
43: if (CSLGlobal::IsValidHandle(_Module.m_hNeverEvent))
00007FF69C7A16C8 48 8D 0D C1 13 0E 00 lea rcx,[_Module+550h (07FF69C882A90h)]
00007FF69C7A16CF E8 3C F2 FB FF call __Skyline_Global::CSLGlobal::IsValidHandle (07FF69C760910h)
00007FF69C7A16D4 85 C0 test eax,eax
00007FF69C7A16D6 74 12 je ExecutionThread+5Ah (07FF69C7A16EAh)
44: WaitForSingleObject(_Module.m_hNeverEvent, 15);
00007FF69C7A16D8 BA 0F 00 00 00 mov edx,0Fh
00007FF69C7A16DD 48 8B 0D AC 13 0E 00 mov rcx,qword ptr [_Module+550h (07FF69C882A90h)]
00007FF69C7A16E4 FF 15 16 0B 08 00 call qword ptr [__imp_WaitForSingleObject (07FF69C822200h)]
45: }
00007FF69C7A16EA EB CB jmp ExecutionThread+27h (07FF69C7A16B7h)
46:
47: pInternalManagerObject->DeInit();
00007FF69C7A16EC E8 FF E7 FD FF call CInternalManagerObject::DeInit (07FF69C77FEF0h)
48: }
我想这意味着
帕格
可以在寄存器中找到
RDI
.
这个
Register
窗口提供以下信息:
RAXÂ =Â 0000000000000000
RBXÂ =Â 0000000000000001
RCXÂ =Â 0000000000000000
RDXÂ =Â 0000000000000000
RSIÂ =Â 00000072A1E83220
RDIÂ =Â 00000072A14A9990
...
在前面提到的地方查看内存后,我发现十六进制值如下:
0x00000072A14A9990 98 59 82 9c f6 7f 00 00 01 00 00 00 00 00 08 00 28 d2 28 62 f9 7f 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 50 0e 78 a2 72 00 ËY.Åö...........(Ã(bù...................................P.x¢r.
0x00000072A14A99CE 00 00 ff ff ff ff 00 00 00 00 00 00 00 00 00 00 00 00 5c 07 00 00 00 00 00 00 d0 07 00 02 00 00 00 00 ff ff ff ff ff ff ff ff ff ff ff ff 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 ..ÿÿÿÿ............\.......Ã.......ÿÿÿÿÿÿÿÿÿÿÿÿ................
0x00000072A14A9A0C 00 00 00 00 d0 07 00 02 00 00 00 00 38 59 82 9c f6 7f 00 00 f0 90 60 a2 72 00 00 00 00 00 00 00 00 00 00 00 09 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 68 59 82 9c f6 7f 00 00 00 00
这是不是意味着
帕格
不是
无效的
的确?(对不起,但我在装配调试方面没有经验)