在Python中将字符串解析为整数时出现问题

你很接近,你的例子中有一个输入错误:-)

sales = '''
Lauren;Tuesday;9
Tim;Wednesday;8
Tim;Thursday;3
Lauren;Friday;1
'''

def salesCalc(sales):
    dic = {}
    for line in sales.splitlines():
        attrs = line.split(";")
     
        if len(attrs) > 1: # this is to make sure that we only consider line with data because we can get '' as line
            # this is just short-cut, it can be also written as
            # if attrs[0] in dic:
            #     dic[attrs[0]] = dic[attrs[0]] + int(attrs[-1])
            # else:
            #     dic[attrs[0]] = int(attrs[-1])
            dic[attrs[0]] = dic[attrs[0]] + int(attrs[-1]) if attrs[0] in dic else int(attrs[-1])
    return dic

print(salesCalc(sales))

sales 输入应该从第一行的数据开始。您的版本以一个空行开始,这导致循环将空字符串作为第一个键/值。第二,你需要把衣服包起来 RHS 词典的 int() ,以处理实际数字。就像以前一样,您正在进行字符串连接。将这两者结合起来:

sales = '''Lauren;Tuesday;9
Tim;Wednesday;8
Tim;Thursday;3
Laurent;Friday;1
'''

def salesCalc(sales):
    dic = {}
    for i in sales.splitlines():
        if i.split(";")[0] in dic:
            dic[i.split(";")[0]] += int(i.split(";")[-1])
        else:
            dic[i.split(";")[0]] = int(i.split(";")[-1])
    return dic

print(salesCalc(sales))  # {'Tim': 11, 'Lauren': 9, 'Laurent': 1}

第一:不需要每次尝试获取元素时都拆分行。 第二:将字符串转换为int使用 int

def salesCalc(sales):
    dic = {}
    for i in sales.splitlines():
        splitted = i.split(";")
        if splitted[0]:
            if splitted[0] in dic:
                dic[splitted[0]] += int(splitted[-1])
            else:
                dic[splitted[0]] = int(splitted[-1])
    return dic