选择字符串中最大的货币值

# Create regular expression pattern for currencies
currency_pattern = re.compile(r"r\$ ([1-9][0-9.]*(?:,[0-9][0-9.]*)?)")

# Find the currencies in the string
currencies = currency_pattern.findall(" da licitação: r$ 43.470,00 (quarenta e três mil, quatrocentos e setenta reais)\n\n3 dos recursos orçamento são r$ 24.123,88")

# Reformat strings and cast to float
normalized_currencies = (float(currency.replace('.', '').replace(',', '.')) for currency in currencies)

# Now we can easily find the maximum value using the `max` function
max_currency = max(normalized_currencies)
print(max_currency)

43470.0个

您可以使用regex执行此任务:

import re

s = ''' da licitação: r$ 43.470,00 (quarenta e três mil, quatrocentos e setenta reais)\n\n3 dos recursos orçamento são r$ 24.123,88'''
m = max(re.findall(r'\d+\.?\d*,?\d*', s), key=lambda v: float(v.replace('.', '').replace(',', '.')), default=None)
print(m)

43.470,00

这样就可以了(返回一个整数!): 我从 here

# Python3 program to extract all the numbers from a string 
import re 

# Function to extract all the numbers from the given string 
def getNumbers(str): 
    array = re.findall(r'[0-9]+', str) 
    return array 

# Driver code 
string = "adbv34.5hj43hvb42"
line = ''
line = re.sub('[!@#$]', '', string)

array = getNumbers(line)

arra_num = []

for nums in array:
    arra_num.append(int(nums))

print(max(arra_num))