方法指针强制转换时如何选择const方法重载[重复]

我有一个重载方法的类:

#include <iostream>
#include <utility>

struct Overloads {
    void foo() {
        std::cout << "foo" << std::endl;
    }

    void foo() const {
        std::cout << "const foo" << std::endl;
    }
};

我知道我可以使用指向成员函数的指针( &Overloads::foo ). 由于这里函数重载 static_cast 必须:

int main() {

    auto overloads = Overloads{};

    auto foo_func = static_cast<void (Overloads::*)()>(&Overloads::foo);

    (overloads.*foo_func)();  // foo is printed - as expected

    // No idea where to put const and why:
    // auto const_foo_func = static_cast<void (Overloads::*) ()>(&Overloads::foo);

    //(overloads.*const_foo_func)();  // const foo output is expected
}

我明白了,如何为非const foo获取一个functor。如何为const foo重载获取一个?