RegEx替换C中的空行++

与其处理“行尾”,我只需用一行新行替换多行连续的新行:

#include <iostream>
#include <string>
#include <regex>

int main(int argc, char **argv) {
    std::string s = "filler text\n\nfiller text";

    std::regex reg("\n+");

    std::cout << "Before:\n";
    std::cout << s << "\nAfter:\n";

    s = std::regex_replace(s, reg, "\n");

    std::cout << '\n' << s << '\n';
}

结果如下:

Before:
filler text

filler text
After:

filler text
filler text