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如何传递R.drawable作为参数,以便解析图像

android java

Mech0z · 技术社区 · 15 年前

我试图保存一个唯一的图像到每个对象,但我得到这个错误,构造函数应该如何寻找它的工作方式? 构造函数(String,int,int)未定义

m_beer = new ArrayList<Beer>();
              final Beer b1 = new Beer("Tuborg", 7, R.drawable.tuborg);
              final Beer b2 = new Beer("Carlsberg", 7, R.drawable.carlsberg);
              final Beer b3 = new Beer("Urquel", 9, R.drawable.urquel);


public class Beer 
{
    //Members
    private String name;
    private int color; //1 = Very dark 10 = Very light
    private R.drawable icon;

    //Methods
    public Beer(String name, int color, R.drawable icon)
    {
        this.name = name;
        this.color = color;
        this.icon = icon;
    }

    public String getName()
    {
        return name;
    }
    public void setName(String name)
    {
        this.name = name;
    }

    public int getColor()
    {
        return this.color;
    }
    public void setColor(int color)
    {
        this.color = color;
    }

    public R.drawable getIcon()
    {
        return icon;
    }

}

2 回复 | 直到 15 年前

Waza_Be 15 年前

final Beer b1 = new Beer("Tuborg", 7,context.getResources().getDrawable(R.drawable.tuborg));

就像之前说的:

public Beer(String name, int color, Drawable icon)

final Beer b1 = new Beer("Tuborg", 7, R.drawable.tuborg);

以及:

public Beer(String name, int color, int icon)
{
    this.name = name;
    this.color = color;
    this.icon = context.getResources().getDrawable(icon);
}