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如何在java中传递不同的构造函数作为响应

java

Priyantha Lokesh Gupta · 技术社区 · 6 年前

响应.java

public class Response{

private String mobileNo;
private String contractId;
private String sim;
private String imei;

public Response(String mobileNo, String contractId){
    this.mobileNo = mobileNo;
    this.contractId = contractId;

}

public Response(String mobileNo, String contractId, String sim,
        String imei, String identificationType) {
    this.mobileNo = mobileNo;
    this.contractId = contractId;
    this.sim = sim;
    this.imei = imei;
    this.identificationType = identificationType;
}



//Getter and Setter

}

MainEx.java公司

public class MainEx{

   Response  response = null;  

   public Response response(){

     String mobileNo = null;
     String contractId = null;
     String sim = null;
     String imei = null;

     if(something){
        response= new IVRAccountDetailsRs("777","4545"); 
     }
     else{
        response= new IVRAccountDetailsRs("777","4545","sim","imei");
     }
    return response;
   }
}

When if语句调用返回响应为

{ "mobileNo" = "777";
  "contractId" = "4545";
  "sim"= null;
  "imei" = null;
}

但我想得到如下的回应,

调用if语句时

需要删除其他两个值。

{ "mobileNo" = "777";
  "contractId" = "4545";
}

如果compressed和mobileNo为空,则输出应为

{ "mobileNo" = null;
  "contractId" = null;
}

调用else语句时

{ "mobileNo" = "777";
  "contractId" = "4545";
  "sim"= "sim";
  "imei" = "imei";
}

如果所有值都为空

 { "mobileNo" = null;
      "contractId" = null;
      "sim"= null;
      "imei" =null;
    }

二手杰克逊版本是2.4.1

我能怎么办?

5 回复 | 直到 6 年前

Frighi 6 年前

你所要求的不可能仅仅通过序列化来管理。

我建议编辑Response类,删除当它们为空时不希望发送的字段。

然后创建另一个扩展Response的类,该类包含其他两个字段。

此时,您可以根据条件实例化所需的对象,并作为响应对象返回。

public class SimpleResponse {
    String mobileNo;
    String contractId;

    .....getters setters
}



public class FullResponse extends SimpleResponse {
    String sim;
    String imei;

    ....getter and setters
}

Destiny.Wang 6 年前

如果SpringBoot的版本低于1.3,则只能以编程方式处理它

@JsonSerialize(include=JsonSerialize.Inclusion.NON_NULL)
public class Response {
    ///~
}

可以直接从 application.properties 文件

spring.jackson.default-property-inclusion=non_null

Official documentation for the jacksong configuration

你可以用 @JsonInclude(JsonInclude.Include.NON_NULL) 在sim和imei上,不是在全班上

public class Response{

private String mobileNo;
private String contractId;
@JsonInclude(JsonInclude.Include.NON_NULL)
private String sim;
@JsonInclude(JsonInclude.Include.NON_NULL)
private String imei;

public Response(String mobileNo, String contractId){
    this.mobileNo = mobileNo;
    this.contractId = contractId;

}

public Response(String mobileNo, String contractId, String sim,
        String imei, String identificationType) {
    this.mobileNo = mobileNo;
    this.contractId = contractId;
    this.sim = sim;
    this.imei = imei;
    this.identificationType = identificationType;
}

GolamMazid Sajib 6 年前

如果你使用 jackson 然后添加:

@JsonInclude(JsonInclude.Include.NON_NULL) before field.

public class Response{

private String mobileNo;
private String contractId;
@JsonInclude(JsonInclude.Include.NON_NULL)
private String sim;
@JsonInclude(JsonInclude.Include.NON_NULL)
private String imei;
}

Beri 6 年前

对于杰克逊系列:

您可以在类上使用注释,以 skip serializing null values :

@JsonInclude(Include.NON_NULL)
public class Response{...}

或者将参数添加到ObjectMapper配置中:

mapper.setSerializationInclusion(Include.NON_NULL);

这可能是 duplicate .

更新:

您也可以注释 properties .

@JsonInclude(JsonInclude.Include.NON_NULL)
private String sim;
@JsonInclude(JsonInclude.Include.NON_NULL)
private String imei;

这样,其他属性将序列化空值,但这两个属性不会用空值序列化。

Frighi 6 年前

在sim和imei的getter上面添加这个注释

 @JsonInclude(Include.NON_NULL)

使用Jackson>1.9.11和<2.x

  @JsonSerialize

注释:

   @JsonSerialize(include=JsonSerialize.Inclusion.NON_NULL)

对于以上版本2:

 @JsonInclude(JsonInclude.Include.NON_NULL)