代码之家 › 专栏 › 技术社区 › Michal

在THREE.js中为螺旋星系生成粒子

spiral three.js random math javascript

Michal · 技术社区 · 7 年前

我想创建一个简单的螺旋星系使用 THREE.Points 在e.js。

fiddle . 有一个扁平的球体,但没有旋臂。

const scene = new THREE.Scene()
const camera = new THREE.PerspectiveCamera(50, window.innerWidth / window.innerHeight)
camera.position.z = 1500
scene.add(camera)
const renderer = new THREE.WebGLRenderer({ clearColor: 0x000000 })
renderer.setSize(window.innerWidth, window.innerHeight)
document.body.appendChild(renderer.domElement)

// Random function with normal dustribution.
const normalRandom = (mean, std) => {
    let n = 0
    
    for (let i = 1; i <= 12; i++) {
      n += Math.random()
    }

    return (n - 6) * std + mean
}

const geometry = new THREE.Geometry()
const galaxySize = 1000

// Generate particles for spiral galaxy:
for (let i = 0; i < 10000; i++) {
  var theta = THREE.Math.randFloatSpread(360) 
  var phi = THREE.Math.randFloatSpread(360)
  const distance = THREE.Math.randFloatSpread(galaxySize)

  // Here I need to generate spiral arms instead of a sphere.
  geometry.vertices.push(new THREE.Vector3(
  	 distance * Math.sin(theta) * Math.cos(phi),
     distance * Math.sin(theta) * Math.sin(phi),
     distance * Math.cos(theta) / 10
  ))
}

const spiralGalaxy = new THREE.Points(geometry, new THREE.PointsMaterial({ color: 0xffffff }))
scene.add(spiralGalaxy)

function render() {
    requestAnimationFrame(render)
    renderer.render(scene, camera)
    spiralGalaxy.rotation.x += 0.01;
    spiralGalaxy.rotation.y += 0.01;
}

render()

<script src="https://cdnjs.cloudflare.com/ajax/libs/three.js/102/three.min.js"></script>

0 回复 | 直到 7 年前

M - 7 年前

看起来你已经用极坐标系做了很多繁重的工作。但是,请记住,角度是以弧度为单位的,而不是以度为单位的,因此不要使用 360 ,您应该使用 PI * 2 . 现在你要做的就是两者都增加 distance theta 同时创造一个螺旋,而 phi

距离 将从 0 到 galaxySize
将从 0 Math.PI (或 π*2 ,如果您想要更紧密的螺旋)
保持接近0

// Temp variables to assign new values inside loop
var norm, theta, phi, thetaVar, distance;

// Generate particles for spiral galaxy:
for (let i = 0; i < 1000; i++) {
    // Norm increments from 0 to 1
    norm = i / 1000;

    // Random variation to theta [-0.5, 0.5]
    thetaVar = THREE.Math.randFloatSpread(0.5);

    // Theta grows from 0 to Math.PI (+ random variation)
    theta = norm * Math.PI + thetaVar;

    // Phi stays close to 0 to create galaxy ecliptic plane
    phi = THREE.Math.randFloatSpread(0.1);

    // Distance grows from 0 to galaxySize
    distance = norm * galaxySize;

    // Here I need generate spiral arms instead of sphere.
    geometry.vertices.push(new THREE.Vector3(
        distance * Math.sin(theta) * Math.cos(phi),
        distance * Math.sin(theta) * Math.sin(phi),
        distance * Math.cos(theta)
    ));
}

你可以为每只手臂创建一个环。请注意,我没有像您在示例中那样在末尾除以10,而是将phi的范围限制为 [-0.1, 0.1] in this fiddle