如何在for循环(datetime)中跨出一周(7天)

使用步骤为7的范围对象,并将其添加到开始日期:

import datetime

def daterange(startdate, enddate, steps=1): 
    """Yields dates in increments of steps days from startdate to enddate"""
    numdays = (enddate-startdate).days 
    for x in range (0, numdays, steps):
        yield startdate + datetime.timedelta(days = x)


today = datetime.datetime.today() 
end = today + datetime.timedelta(days=40)

print( list(daterange(today, end, 7)))

[datetime.datetime(2018, 9, 28, 19, 34, 26, 976681), 
 datetime.datetime(2018, 10, 5, 19, 34, 26, 976681), 
 datetime.datetime(2018, 10, 12, 19, 34, 26, 976681), 
 datetime.datetime(2018, 10, 19, 19, 34, 26, 976681), 
 datetime.datetime(2018, 10, 26, 19, 34, 26, 976681), 
 datetime.datetime(2018, 11, 2, 19, 34, 26, 976681)]

只需在循环中添加步长:

from datetime import timedelta, date

def daterange(start_date, end_date):
     for n in range(0, int((end_date - start_date).days) + 1, 7):
         yield start_date + timedelta(n)

start_dt = date(2018, 9, 1)
end_dt = date(2018, 10, 30)
for dt in daterange(start_dt, end_dt):
    print(dt.strftime("%Y-%m-%d"))

输出:

2018-09-01
2018-09-08
2018-09-15
2018-09-22
2018-09-29
2018-10-06
2018-10-13
2018-10-20
2018-10-27