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SpringSecurity需要ContextLoaderListener,但我使用的是带注释的配置,怎么办?

spring-security spring java

5

Matt W · 技术社区 · 15 年前

@ImportResource("security-config.xml") 加载安全配置。配置bean创建得很好。我的网站.xml看起来是这样的:

<?xml version="1.0" encoding="UTF-8"?>
<web-app id="com-timbuk2-webapp-compositor" 
         version="3.0"
         xmlns="http://java.sun.com/xml/ns/javaee" 
         xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" 
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
         xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
                             http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" >

    <!-- Spring Security Chain -->
    <filter>
         <filter-name>springSecurityFilterChain</filter-name>
         <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
    </filter>

    <filter-mapping>
       <filter-name>springSecurityFilterChain</filter-name>
       <url-pattern>/*</url-pattern>
    </filter-mapping>

     <!--  Character Encoding -->
    <filter>
        <filter-name>characterEncodingFilter</filter-name>
        <filter-class>org.springframework.web.filter.CharacterEncodingFilter</filter-class>
        <init-param>
            <param-name>encoding</param-name>
            <param-value>UTF-8</param-value>
        </init-param>
        <init-param>
            <param-name>forceEncoding</param-name>
            <param-value>true</param-value>
        </init-param>
    </filter>

    <filter-mapping>
        <filter-name>characterEncodingFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

    <!--  URL Rewrite -->
    <filter>
        <filter-name>urlRewriteFilter</filter-name>
        <filter-class>org.tuckey.web.filters.urlrewrite.UrlRewriteFilter</filter-class>
        <init-param>
            <param-name>logLevel</param-name>
            <param-value>commons</param-value>
        </init-param>
        <init-param>
            <param-name>confPath</param-name>
            <param-value>/WEB-INF/conf/urlrewrite-config.xml</param-value>
        </init-param>
    </filter>

    <filter-mapping>
        <filter-name>urlRewriteFilter</filter-name>
        <url-pattern>/*</url-pattern>
    </filter-mapping>

    <!-- Listeners -->
    <listener>
        <listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
    </listener>

    <!-- Context Parameters -->
    <context-param>
        <param-name>log4jConfigLocation</param-name>
        <param-value>/WEB-INF/conf/log4j-config.xml</param-value>
    </context-param>

    <!-- Servlets -->
    <servlet>
        <servlet-name>app-dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextClass</param-name>
            <param-value>org.springframework.web.context.support.AnnotationConfigWebApplicationContext</param-value>
        </init-param>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>com.website.config</param-value>
        </init-param>
        <load-on-startup>0</load-on-startup>
    </servlet>

    <!-- Servlet mappings -->
    <servlet-mapping>
        <servlet-name>app-dispatcher</servlet-name>
        <url-pattern>/app/*</url-pattern>
    </servlet-mapping>


</web-app>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

给我的网站.xml我的应用程序没有初始化。有没有办法在我的注解配置中手动创建ContextLoaderListener?

2 回复 | 直到 12 年前

1

2

Betlista 12 年前

只需使用ContextLoaderListener创建根应用程序上下文。

<context-param>
    <description>The Spring configuration files.</description>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/spring/application.xml</param-value>
</context-param>

<listener>
    <description>The Spring context listener.</description>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

内部应用程序.xml,还可以定义基于注释的配置。它将由DispatcherServlet定义的WebApplicationContext继承。

然后将安全配置导入应用程序.xml. 因此,安全性将应用于配置中的所有ApplicationContext。

2

0

Betlista 12 年前

我相信它可以与以下网页应用程序下的添加

<context-param>
  <param-name>contextClass</param-name>
  <param-value>
    org.springframework.config.java.context.JavaConfigWebApplicationContext
  </param-value>
</context-param>
<context-param>
  <param-name>contextConfigLocation</param-name>
  <param-value>com.website.config</param-value>
</context-param>

资料来源: http://blog.springsource.com/2008/03/26/spring-java-configuration-whats-new-in-m3/

3

0

SongChay Beng 5 年前

<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>classpath:/appcontext-root.xml</param-value>
</context-param>

<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>