代码之家 › 专栏 › 技术社区 › Paris B. G.

动态地从导航视图(抽屉)检索Android /Java

navigationview drawer object android java

1

Paris B. G. · 技术社区 · 7 年前

再一次陷入死在我的编码轨道,我来从无所不知的StackOverflow社区寻求知识… 我的问题相当简单。我用对象填充了一个导航视图抽屉。这些对象toString()方法已被覆盖,以在列表中显示每个对象的名称。单击抽屉列表中的每个对象都会显示一条警告消息,该消息应该说(“You clicked”+MyDrawerObject.getName())问题出现在OnNavigationItemSelected侦听器中。此方法返回一个作为视图的menuItem项。我很难理解为什么我不能把这个视图视为它应该包含的对象。非常感谢您的帮助,并提前表示感谢!

我知道item参数正在返回已单击的菜单项,但如果菜单项是对象,为什么我不能调用这些对象方法? 我试图获取项目返回值并调用它的getname()方法,但没有用。item.getname();(我了解该项是一个视图,因此它没有“getname()”方法

我试图将项目值重新转换为一个对象,但没有效果 myObject myObject=(myObject)项; //项仍然是一个视图,不能将视图强制转换为对象

我甚至尝试将所有创建的MyObject类型的对象放入静态ArrayList,然后尝试匹配ID也没有用。 //在OnNavigationItemSelected侦听器中 int id=item.getitemid()。

//somewhere else in the code
 for (anotherMyObject : listOfEveryMyObjectEverMade){
 anotherMyObject.get(id)
 }
/*returns the id of the item in the listview. as i understand a specific id 
is assigned to every item in the list. so if an object has never been in that 
particular list, it wont have that same id
*/

我必须添加抽屉的内容(字符串列表)是动态创建的,所以没有菜单或menitems的XML文件!

1 回复 | 直到 7 年前

1

0

Paris B. G. 6 年前

我遇到了一个非常相似的情况,实际上封锁了我好几天!

我几乎90%的人认为必须有一条出路…

但我个人没有找到它,所以我去了一个工作:

private void setMenus() {
    int temp = 0;
  //Mine was inside of a fragment, hints the getActivity() call
    NavigationView navView22 = getActivity().findViewById(R.id.navigation_view);
    MenuItem oneItem = navView22.getMenu().findItem(0);
        if (oneItem == null){
        Menu m = navView22.getMenu();
        SubMenu sm0 = m.addSubMenu(
                getResources().getString(R.string.clickToSelectRookies));
        sm0.add(0,
                temp, temp, getResources().getString(R.string.signAllString));
            tempRooks.add(round1.get(0));
  /*I had to create the entire menu dynamically, so I did so by creating 
  subMenus in my menus in numerical order
  I then created an arraylist to hold all my objects in that same order
  though in retrospect I should have just used a HashMap!!
  finally in the onClick I was able to listen for which subMenu item was clicked
   and since the menu's and my arraylist of objects corresponded I then pulled 
  the correct object from my arraylist. I realize this is a little hacky, but 
  hopefully if you do not find the answer you can do this temporarily.
  If you do find a better solution please post so we all can learn. Thank YOU!!

*/ 温度++;

        SubMenu sm1 = m.addSubMenu(
                getResources().getString(R.string.firstRoundPicks));
        for (int x = 0; x < round1.size(); x++) {
            sm1.add(0, temp, temp, round1.get(x).toString());
                tempRooks.add(round1.get(x));
            temp++;
        }